Question

这是我在这里发表的第一篇文章，感谢您的及时支持。

我在一个大文件上做了一些greps，并附带了如下文件。我希望在同一行的XX @开头之后创建所有行。

所以，我想要流动：

XX@DEV1> 
Feb 23 07:00:03
Feb 23 07:00:05
Sent : 4608
Received : 4227
Feb 23 07:00:07
Feb 23 07:00:09

XX@DEV2> 
Feb 23 07:00:32
Feb 23 07:00:34
Sent : 4608
Received : 4232
Feb 23 07:00:36
Feb 23 07:00:38

XX@DEV1> 
Feb 23 08:00:03
Feb 23 08:00:06
Sent : 4608
Received : 4265
Feb 23 08:00:07
Feb 23 08:00:09

XX@DEV2>
...

成为：

XX@DEV1> Feb 23 07:00:03 Feb 23 07:00:05 Sent : 4608 Received : 4227 Feb 23 07:00:07 Feb 23 07:00:09

XX@DEV2> Feb 23 07:00:32 Feb 23 07:00:34 Sent : 4608 Received : 4232 Feb 23 07:00:36 Feb 23 07:00:38

XX@DEV1> Feb 23 08:00:03 Feb 23 08:00:06 Sent : 4608 Received : 4265 Feb 23 08:00:07 Feb 23 08:00:09

XX@DEV2> ...

Answer 1

你可以很容易地用 awk 做到这一点：

awk '/^XX/{if(length(out))print out;out=$0;next}{out=out" "$0}END{print out}' yourfile

那说..如果行以“XX”开头，打印我们在变量out中累积的任何内容，然后将当前行保存在变量out中。如果该行是其他任何内容，请在添加空格后将其附加到变量out。最后，打印我们在变量out中积累的任何内容。

输出：

XX@DEV1>  Feb 23 07:00:03 Feb 23 07:00:05 Sent : 4608 Received : 4227 Feb 23 07:00:07 Feb 23    07:00:09
XX@DEV2>  Feb 23 07:00:32 Feb 23 07:00:34 Sent : 4608 Received : 4232 Feb 23 07:00:36 Feb 23 07:00:38
XX@DEV1>  Feb 23 08:00:03 Feb 23 08:00:06 Sent : 4608 Received : 4265 Feb 23 08:00:07 Feb 23 08:00:09

Answer 2

或者你可以用 bash 和我的其他答案中的 awk 一样：

#!/bin/bash
while read line
do
    if [[ $line == XX* ]] ;then
      echo $OUT         # Output whatever we have accumulated in $OUT
      OUT=$line         # Zero out $OUT and restart accumulating
    else
      OUT="$OUT $line"  # Append this line to $OUT
    fi
done < yourfile
echo $OUT               # Output any trailing stuff at the end

Answer 3

sed -n '
  # use -n to prevent sed from printing each line
  # if the line read starts with XX, go (b) to :printit
  /^XX/ b printit
  # if it is the last line ($), also go to :printit
  $ b printit
  # for all other lines, append the read line to the hold space (H)
  # and then go to the :end (so we read the next line)
  H; b end

:printit {
  # swap the hold and the pattern space
  x
  # replace all (s/../../g) single or multiple newlines (\n\n*)
  #   with a space
  s/\n\n*/ /g
  # print the pattern space
  p
}

:end
' your_file

Shell：用两条特定行之间的空格替换\ n

3 个答案: