Question

尝试让我的PHP导航栏工作。如果页面是最新的，我试图回显用户所在的页面以及附加的活动类。

这是我的代码。它显示了链接，我可以浏览网站，但它忽略了活动类。悬停工程和链接的样式。它只是忽略了活动类。

<?php
$pages = array(
    "index.php" => "Home", 
    "pages/contact.php" => "Contact Us", 
    "pages/services.php" => "services", 
    "pages/employees.php" => "Employees", 
    "pages/dashboard.php" => "Dashboard");

foreach ($pages as $url => $label) {
  echo '<li ';

  if (isset($_GET['page']) && $_GET['page'] == $url) {
    echo '"class=active"';
  }
  echo '><a href=', "$url", '>', "$label", '</a></li>';
}
?>

Answer 1

试试这个：

echo 'class="active"';

Answer 2

这样做：

$pages = array(
    "index.php" => "Home", 
    "pages/contact.php" => "Contact Us", 
    "pages/services.php" => "services", 
    "pages/employees.php" => "Employees", 
    "pages/dashboard.php" => "Dashboard");

foreach ($pages as $url => $label) {
  echo '<li ';

  if(basename($_SERVER['REQUEST_URI'])== basename($url)){   // this line
        echo "class='active'";                              // this line
   }                                                        // and this line
  echo '><a href=', "$url", '>', "$label", '</a></li>';
}
?>

Answer 3

<?php 

if ($_SERVER['REQUEST_URI'] === "/page") echo 'id="active"'; 

?>

Answer 4

未经测试：

<?php
$pages = array(
    "index.php" => "Home", 
    "contact.php" => "Contact Us", 
    "services.php" => "services", 
    "employees.php" => "Employees", 
    "dashboard.php" => "Dashboard");

$uri = explode("/", stripslashes($_SERVER['REQUEST_URI']));

foreach ($pages as $url => $label) {
  echo '<li ';
  echo in_array($url, $uri)?'class="active"':'';
  echo '><a href="'.$url.'">'.$label.'</a></li>';
}
?>

注意：最好将其他页面文件放在你的index.php旁边的根目录中

Answer 5

<?php
$pages = array(
    "index.php" => "Home", 
    "pages/contact.php" => "Contact Us", 
    "pages/services.php" => "services", 
    "pages/employees.php" => "Employees", 
    "pages/dashboard.php" => "Dashboard");

$cururl = $_SERVER['PHP_SELF'];

foreach ($pages as $url => $label) {
  echo '<li';

  if (strpos($cururl,$url)!==false) {
    echo ' class="active"';
  }
  echo '><a href=', "$url", '>', "$label", '</a></li>';
}
?>

这对你有用。因为，您尝试使用GET-METHOD访问网址。在这里，我通过$cururl = $_SERVER['PHP_SELF'];获取了您的网址并检查了活动菜单项if (strpos($cururl,$url)!==false)

如何用php添加active到标签和li标签

5 个答案: