Question

我有下一个问题。当我以表格发送POST请求时：

<form id="uploadForm" action="/theme/zip/type/" method="post" enctype="multipart/form-data">
    {% csrf_token %}
    <input id="fileInput" class="input-file" name="upload" type="file">
    <input type="submit" value="Upload" />
</form>

然后在服务器上我有代码：

print request.FILES

服务器打印：

<MultiValueDict: {u'upload': [<InMemoryUploadedFile: ID_12241.zip (application/zip)>]}>

当我在jQuery代码中逐步执行此操作时：

var content = zip.generate();
var options = {
    url: '/theme/zip/type/',
    data: {
       file: content
    }
};
$('#uploadForm').ajaxSubmit(options);

我在'request.POST'中的'file'参数中有这个文件，但是'request.FILES'是空的（）。我做错了什么？

Answer 1

查看JQUery Form Plugin，它能够使用ajax上传文件。

根据其网站上的文档

Browsers that support the XMLHttpRequest Level 2 will be able to upload files seamlessly and even get progress updates as the upload proceeds. For older browsers, a fallback technology is used which involves iframes since it is not possible to upload files using the level 1 implmenentation of the XMLHttpRequest object.

我在我的项目中使用它，您不必为旧浏览器定义任何iframe。这个插件会自动为你做。下面是实现ajax文件上传的示例代码 -

HTML文件看起来像（下载并链接html文件中的jquery.form.js）： -

<form id="uploadForm" method="post" action="/theme/zip/type/"> {% csrf_token %}
    <input type="file" id="fileInput" name="upload"/>
    <button type="submit">Upload</button>
</form>

<script src="jquery-ui.min.js"></script>
<script src="jquery.form.js"></script>

在js文件中添加以下代码： -

var options = {
    beforeSubmit:showRequest,  // pre-submit callback
    success:showResponse,  // post-submit callback
    resetForm: false        // reset the form after successful submit
};

//uploadForm is the name of your form
$('#uploadForm').submit(function() {
    // inside event callbacks 'this' is the DOM element so we first
    // wrap it in a jQuery object and then invoke ajaxSubmit

    $(this).ajaxSubmit(options);

    // !!! Important !!!
    // always return false to prevent standard browser submit and 
    // page navigation return false;
});

// pre-submit callback 
function showRequest(formData, jqForm, options) { 
    // formData is an array; here we use $.param to convert it 
    // to a string to display it but the form plugin does 
    // this for you automatically when it submits the data 
    var queryString = $.param(formData); 

    // jqForm is a jQuery object encapsulating the form element. 
    // To access the DOM element for the form do this: 
    // var formElement = jqForm[0]; 

    alert('About to submit: \n\n' + queryString); 

    // here we could return false to prevent the form from being submitted; 
    // returning anything other than false will allow the 
    // form submit to continue 
    return true; 
} 

// post-submit callback 
function showResponse(responseText, statusText, xhr, $form)  { 
    // for normal html responses, the first argument to the success callback 
    // is the XMLHttpRequest object's responseText property 

    // if the ajaxSubmit method was passed an Options Object with the dataType 
    // property set to 'xml' then the first argument to the success callback 
    // is the XMLHttpRequest object's responseXML property 

    // if the ajaxSubmit method was passed an Options Object with the dataType 
    // property set to 'json' then the first argument to the success callback 
    // is the json data object returned by the server 

    alert('status: ' + statusText + '\n\nresponseText: \n' + responseText + 
        '\n\noutput div should have been updated with the responseText.'); 
}

单击提交按钮后，将调用.submit（）函数。此函数返回false，这对于防止浏览器回发很重要。在此功能中，定义了2个回调函数。

showRequest将被调用，在这里您可以看到所有的帖子数据。
showResponse。

在服务器上，您将获取request.FILES中的数据。从服务器返回JSON响应，可以在showResponse函数中访问。

Answer 2

传统意义上的Ajax是XMLHttpRequest，它不允许您编码本地文件并将其发送到服务器。

通过“ajax”进行上传的常用方法是使用Flash swf处理同一页面上的内容，或者使用目标为不可见的1x1 iframe的表单。

试

http://net.tutsplus.com/tutorials/javascript-ajax/uploading-files-with-ajax/

或尝试http://www.uploadify.com/

JQuery将文件发送到Django

2 个答案: