如何在Eclipse中运行servlet?

时间:2014-02-22 02:33:37

标签: java eclipse tomcat servlets

安装细节:

首先我安装jdk然后添加一个环境变量

变量名=“路径”

变量值=“C:\ Program Files \ Java \ jdk1.7.0_45 \ bin”(java目录)

然后解压缩eclipse和tomcat

解压后,我从apache-tomcat-7.0.23 \ bin编辑catalina.bat并添加: “设置JAVA_HOME = C:\ Program Files \ Java \ jdk1.7.0_45”

然后我通过创建新的动态Web项目

创建了我的第一个Servlet
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Test Form</title>
</head>
<body>

<h1>JAVA TEST</h1>

<form action ="work.html" method ="get">

<input type="submit" value="login">
</form>



</body>
</html>

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

/**
 * Servlet implementation class work
 */
@WebServlet("/work.html")
public class work extends HttpServlet {
    private static final long serialVersionUID = 1L;

    /**
     * @see HttpServlet#HttpServlet()
     */
    public work() {
        super();
        // TODO Auto-generated constructor stub
    }

    /**
     * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        response.setContentType("text/html");
        PrintWriter out = response.getWriter();

        out.print("<html>");
        out.print("<head>");
        out.print("<title>Login Authentication Result</title>");
        out.print("<h2>Welcome to servlet</h2>");
        out.print("<p> powered by" + getServletContext().getServerInfo()+ "</p>");
        out.print("</body>");
        out.print("</hmtl>");
        out.close();
    }

    /**
     * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        // TODO Auto-generated method stub
    }

}

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
  <display-name>Test3</display-name>
  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>
</web-app>

enter image description here

我是servlet的新手。我不知道为什么单击index.html

中的按钮时总会出现此错误

enter image description here

我想我有problem

1 个答案:

答案 0 :(得分:0)

只需在eclipse中配置Tomcat!