我在Chrome 33中尝试使用语音合成API时遇到了问题。它与较短的文本完美配合，但如果我尝试更长的文本，它就会停在中间。在它停止一次之后，语音合成在浏览器重新启动之前无法在Chrome中的任何位置工作。
示例代码（http://jsfiddle.net/Mdm47/1/）：
function speak(text) {
var msg = new SpeechSynthesisUtterance();
var voices = speechSynthesis.getVoices();
msg.voice = voices[10];
msg.voiceURI = 'native';
msg.volume = 1;
msg.rate = 1;
msg.pitch = 2;
msg.text = text;
msg.lang = 'en-US';
speechSynthesis.speak(msg);
}
speak('Short text');
speak('Collaboratively administrate empowered markets via plug-and-play networks. Dynamically procrastinate B2C users after installed base benefits. Dramatically visualize customer directed convergence without revolutionary ROI. Efficiently unleash cross-media information without cross-media value. Quickly maximize timely deliverables for real-time schemas. Dramatically maintain clicks-and-mortar solutions without functional solutions.');
speak('Another short text');
它停止在第二个文本的中间发言，在此之后我无法发表任何其他页面。
是浏览器错误还是某种安全限制？
答案 0 :(得分：50)
我已经有一段时间使用谷歌Chrome语音合成这个问题了。经过一番调查，我发现了以下内容：
speechSynthesis.cancel(); 为了回应这些问题，我编写了一个能够克服字符限制的函数，将文本分成较小的话语，然后一个接一个地播放。显然你会得到一些奇怪的声音，因为句子可能被分成两个单独的话语，每个话语之间有一个小的时间延迟，然而代码会尝试将这些点分成标点符号，以便声音中断不太明显。
<强>更新
我已在https://gist.github.com/woollsta/2d146f13878a301b36d7#file-chunkify-js公开发布这项解决方案。非常感谢Brett Zamir的贡献。
功能：
var speechUtteranceChunker = function (utt, settings, callback) {
settings = settings || {};
var newUtt;
var txt = (settings && settings.offset !== undefined ? utt.text.substring(settings.offset) : utt.text);
if (utt.voice && utt.voice.voiceURI === 'native') { // Not part of the spec
newUtt = utt;
newUtt.text = txt;
newUtt.addEventListener('end', function () {
if (speechUtteranceChunker.cancel) {
speechUtteranceChunker.cancel = false;
}
if (callback !== undefined) {
callback();
}
});
}
else {
var chunkLength = (settings && settings.chunkLength) || 160;
var pattRegex = new RegExp('^[\\s\\S]{' + Math.floor(chunkLength / 2) + ',' + chunkLength + '}[.!?,]{1}|^[\\s\\S]{1,' + chunkLength + '}$|^[\\s\\S]{1,' + chunkLength + '} ');
var chunkArr = txt.match(pattRegex);
if (chunkArr[0] === undefined || chunkArr[0].length <= 2) {
//call once all text has been spoken...
if (callback !== undefined) {
callback();
}
return;
}
var chunk = chunkArr[0];
newUtt = new SpeechSynthesisUtterance(chunk);
var x;
for (x in utt) {
if (utt.hasOwnProperty(x) && x !== 'text') {
newUtt[x] = utt[x];
}
}
newUtt.addEventListener('end', function () {
if (speechUtteranceChunker.cancel) {
speechUtteranceChunker.cancel = false;
return;
}
settings.offset = settings.offset || 0;
settings.offset += chunk.length - 1;
speechUtteranceChunker(utt, settings, callback);
});
}
if (settings.modifier) {
settings.modifier(newUtt);
}
console.log(newUtt); //IMPORTANT!! Do not remove: Logging the object out fixes some onend firing issues.
//placing the speak invocation inside a callback fixes ordering and onend issues.
setTimeout(function () {
speechSynthesis.speak(newUtt);
}, 0);
};
如何使用它......
//create an utterance as you normally would...
var myLongText = "This is some long text, oh my goodness look how long I'm getting, wooooohooo!";
var utterance = new SpeechSynthesisUtterance(myLongText);
//modify it as you normally would
var voiceArr = speechSynthesis.getVoices();
utterance.voice = voiceArr[2];
//pass it into the chunking function to have it played out.
//you can set the max number of characters by changing the chunkLength property below.
//a callback function can also be added that will fire once the entire text has been spoken.
speechUtteranceChunker(utterance, {
chunkLength: 120
}, function () {
//some code to execute when done
console.log('done');
});
希望人们觉得这很有用。
答案 1 :(得分：8)
Peter回答的问题是，当你设置了一个语音合成队列时它不起作用。该脚本将新的块放在队列的末尾，因此不按顺序排列。示例：https://jsfiddle.net/1gzkja90/
<script type='text/javascript' src='http://code.jquery.com/jquery-2.1.0.js'></script>
<script type='text/javascript'>
u = new SpeechSynthesisUtterance();
$(document).ready(function () {
$('.t').each(function () {
u = new SpeechSynthesisUtterance($(this).text());
speechUtteranceChunker(u, {
chunkLength: 120
}, function () {
console.log('end');
});
});
});
/**
* Chunkify
* Google Chrome Speech Synthesis Chunking Pattern
* Fixes inconsistencies with speaking long texts in speechUtterance objects
* Licensed under the MIT License
*
* Peter Woolley and Brett Zamir
*/
var speechUtteranceChunker = function (utt, settings, callback) {
settings = settings || {};
var newUtt;
var txt = (settings && settings.offset !== undefined ? utt.text.substring(settings.offset) : utt.text);
if (utt.voice && utt.voice.voiceURI === 'native') { // Not part of the spec
newUtt = utt;
newUtt.text = txt;
newUtt.addEventListener('end', function () {
if (speechUtteranceChunker.cancel) {
speechUtteranceChunker.cancel = false;
}
if (callback !== undefined) {
callback();
}
});
}
else {
var chunkLength = (settings && settings.chunkLength) || 160;
var pattRegex = new RegExp('^[\\s\\S]{' + Math.floor(chunkLength / 2) + ',' + chunkLength + '}[.!?,]{1}|^[\\s\\S]{1,' + chunkLength + '}$|^[\\s\\S]{1,' + chunkLength + '} ');
var chunkArr = txt.match(pattRegex);
if (chunkArr[0] === undefined || chunkArr[0].length <= 2) {
//call once all text has been spoken...
if (callback !== undefined) {
callback();
}
return;
}
var chunk = chunkArr[0];
newUtt = new SpeechSynthesisUtterance(chunk);
var x;
for (x in utt) {
if (utt.hasOwnProperty(x) && x !== 'text') {
newUtt[x] = utt[x];
}
}
newUtt.addEventListener('end', function () {
if (speechUtteranceChunker.cancel) {
speechUtteranceChunker.cancel = false;
return;
}
settings.offset = settings.offset || 0;
settings.offset += chunk.length - 1;
speechUtteranceChunker(utt, settings, callback);
});
}
if (settings.modifier) {
settings.modifier(newUtt);
}
console.log(newUtt); //IMPORTANT!! Do not remove: Logging the object out fixes some onend firing issues.
//placing the speak invocation inside a callback fixes ordering and onend issues.
setTimeout(function () {
speechSynthesis.speak(newUtt);
}, 0);
};
</script>
<p class="t">MLA format follows the author-page method of in-text citation. This means that the author's last name and the page number(s) from which the quotation or paraphrase is taken must appear in the text, and a complete reference should appear on your Works Cited page. The author's name may appear either in the sentence itself or in parentheses following the quotation or paraphrase, but the page number(s) should always appear in the parentheses, not in the text of your sentence.</p>
<p class="t">Joe waited for the train.</p>
<p class="t">The train was late.</p>
<p class="t">Mary and Samantha took the bus.</p>
在我的情况下，答案是在将字符串添加到队列之前将其“chunk”。见这里：http://jsfiddle.net/vqvyjzq4/
很多道具给彼得的想法和正则表达式（我还有待征服。）我确信javascript可以清理，这更像是一个概念证明。
<script type='text/javascript' src='http://code.jquery.com/jquery-2.1.0.js'></script>
<script type='text/javascript'>
var chunkLength = 120;
var pattRegex = new RegExp('^[\\s\\S]{' + Math.floor(chunkLength / 2) + ',' + chunkLength + '}[.!?,]{1}|^[\\s\\S]{1,' + chunkLength + '}$|^[\\s\\S]{1,' + chunkLength + '} ');
$(document).ready(function () {
var element = this;
var arr = [];
var txt = replaceBlank($(element).text());
while (txt.length > 0) {
arr.push(txt.match(pattRegex)[0]);
txt = txt.substring(arr[arr.length - 1].length);
}
$.each(arr, function () {
var u = new SpeechSynthesisUtterance(this.trim());
window.speechSynthesis.speak(u);
});
});
</script>
<p class="t">MLA format follows the author-page method of in-text citation. This means that the author's last name and the page number(s) from which the quotation or paraphrase is taken must appear in the text, and a complete reference should appear on your Works Cited page. The author's name may appear either in the sentence itself or in parentheses following the quotation or paraphrase, but the page number(s) should always appear in the parentheses, not in the text of your sentence.</p>
<p class="t">Joe waited for the train.</p>
<p class="t">The train was late.</p>
<p class="t">Mary and Samantha took the bus.</p>
答案 2 :(得分：5)
我最终对文本进行了整理，并对处理各种惩罚，如句号，逗号等有了一些了解。例如，如果有逗号，你就不想在逗号上打破文本。数字的一部分（即10,000美元）。
我测试了它，它似乎可以处理任意大量的输入，它似乎不仅可以在桌面上工作，还可以在Android手机和iphone上工作。
设置合成器的github页面 看到它答案 3 :(得分：5)
一个简单有效的解决方案是定期恢复。
function resumeInfinity() {
window.speechSynthesis.resume();
timeoutResumeInfinity = setTimeout(resumeInfinity, 1000);
}
您可以将此与onend和onstart事件相关联，因此您只会在必要时调用简历。类似的东西：
var utterance = new SpeechSynthesisUtterance();
utterance.onstart = function(event) {
resumeInfinity();
};
utterance.onend = function(event) {
clearTimeout(timeoutResumeInfinity);
};
我偶然发现了这个！
希望这有帮助！
答案 4 :(得分：3)
这是我最终的结果，它只是将句子分成句点“。”
var voices = window.speechSynthesis.getVoices();
var sayit = function ()
{
var msg = new SpeechSynthesisUtterance();
msg.voice = voices[10]; // Note: some voices don't support altering params
msg.voiceURI = 'native';
msg.volume = 1; // 0 to 1
msg.rate = 1; // 0.1 to 10
msg.pitch = 2; //0 to 2
msg.lang = 'en-GB';
msg.onstart = function (event) {
console.log("started");
};
msg.onend = function(event) {
console.log('Finished in ' + event.elapsedTime + ' seconds.');
};
msg.onerror = function(event)
{
console.log('Errored ' + event);
}
msg.onpause = function (event)
{
console.log('paused ' + event);
}
msg.onboundary = function (event)
{
console.log('onboundary ' + event);
}
return msg;
}
var speekResponse = function (text)
{
speechSynthesis.cancel(); // if it errors, this clears out the error.
var sentences = text.split(".");
for (var i=0;i< sentences.length;i++)
{
var toSay = sayit();
toSay.text = sentences[i];
speechSynthesis.speak(toSay);
}
}
答案 5 :(得分：3)
2017年，这个错误仍然存在。我碰巧很好地理解了这个问题，成为屡获殊荣的Chrome扩展程序朗读的开发者。好的，只是开玩笑说这个获奖部分。
我使用的解决方法是一个相当复杂的分块算法，它尊重标点符号。对于拉丁语言，我将最大块大小设置为36个字。如果你有意思，代码是开源的：https://github.com/ken107/read-aloud/blob/master/js/speech.js（第144行）
36字的限制在大多数情况下运作良好，保持在15秒内。但是，它仍然会遇到困难的情况。为了从中恢复，我使用16秒计时器。
答案 6 :(得分：2)
我已经解决了问题，同时有一个调用pause（）和resume（）函数的计时器函数，并再次调用计时器。在第一个事件中，我清除了计时器。
var myTimeout;
function myTimer() {
window.speechSynthesis.pause();
window.speechSynthesis.resume();
myTimeout = setTimeout(myTimer, 10000);
}
...
window.speechSynthesis.cancel();
myTimeout = setTimeout(myTimer, 10000);
var toSpeak = "some text";
var utt = new SpeechSynthesisUtterance(toSpeak);
...
utt.onend = function() { clearTimeout(myTimeout); }
window.speechSynthesis.speak(utt);
...
这似乎运作良好。
答案 7 :(得分：0)
正如迈克尔提出的那样，彼得的解决方案非常棒，除非你的文字在不同的行上。迈克尔创建了演示，以更好地说明它的问题。 - https://jsfiddle.net/1gzkja90/并提出了另一种解决方案。
添加一个更简单的方法来解决这个问题就是在Peter的解决方案中删除textarea中的换行符，它的效果非常好。
//javascript
var noLineBreaks = document.getElementById('mytextarea').replace(/\n/g,'');
//jquery
var noLineBreaks = $('#mytextarea').val().replace(/\n/g,'');
所以在彼得的解决方案中，它可能看起来如下：
utterance.text = $('#mytextarea').val().replace(/\n/g,'');
但取消演讲仍然存在问题。它只是进入另一个序列并且不会停止。
答案 8 :(得分：0)
其他建议用圆点或说DOT做奇怪的事情，不要尊重句末的语音语调。
var CHARACTER_LIMIT = 200;
var lang = "en";
var text = "MLA format follows the author-page method of in-text citation. This means that the author's last name and the page number(s) from which the quotation or paraphrase is taken must appear in the text, and a complete reference should appear on your Works Cited page. The author's name may appear either in the sentence itself or in parentheses following the quotation or paraphrase, but the page number(s) should always appear in the parentheses, not in the text of your sentence. Joe waited for the train. The train was late. Mary and Samantha took the bus.";
speak(text, lang)
function speak(text, lang) {
//Support for multipart text (there is a limit on characters)
var multipartText = [];
if (text.length > CHARACTER_LIMIT) {
var tmptxt = text;
while (tmptxt.length > CHARACTER_LIMIT) {
//Split by common phrase delimiters
var p = tmptxt.search(/[:!?.;]+/);
var part = '';
//Coludn't split by priority characters, try commas
if (p == -1 || p >= CHARACTER_LIMIT) {
p = tmptxt.search(/[,]+/);
}
//Couldn't split by normal characters, then we use spaces
if (p == -1 || p >= CHARACTER_LIMIT) {
var words = tmptxt.split(' ');
for (var i = 0; i < words.length; i++) {
if (part.length + words[i].length + 1 > CHARACTER_LIMIT)
break;
part += (i != 0 ? ' ' : '') + words[i];
}
} else {
part = tmptxt.substr(0, p + 1);
}
tmptxt = tmptxt.substr(part.length, tmptxt.length - part.length);
multipartText.push(part);
//console.log(part.length + " - " + part);
}
//Add the remaining text
if (tmptxt.length > 0) {
multipartText.push(tmptxt);
}
} else {
//Small text
multipartText.push(text);
}
//Play multipart text
for (var i = 0; i < multipartText.length; i++) {
//Use SpeechSynthesis
//console.log(multipartText[i]);
//Create msg object
var msg = new SpeechSynthesisUtterance();
//msg.voice = profile.systemvoice;
//msg.voiceURI = profile.systemvoice.voiceURI;
msg.volume = 1; // 0 to 1
msg.rate = 1; // 0.1 to 10
// msg.rate = usersetting || 1; // 0.1 to 10
msg.pitch = 1; //0 to 2*/
msg.text = multipartText[i];
msg.speak = multipartText;
msg.lang = lang;
msg.onend = self.OnFinishedPlaying;
msg.onerror = function (e) {
console.log('Error');
console.log(e);
};
/*GC*/
msg.onstart = function (e) {
var curenttxt = e.currentTarget.text;
console.log(curenttxt);
//highlight(e.currentTarget.text);
//$('#showtxt').text(curenttxt);
//console.log(e);
};
//console.log(msg);
speechSynthesis.speak(msg);
}
}
答案 9 :(得分：0)
是的，谷歌综合api会在说长篇文章时停止。
我们可以看到第一个事件，当突然停止时，SpeechSynthesisUtterance的onpause和onerror事件不会被正常触发，speechSynthesis onerror事件也是如此。
因此我们只需要一个计时器来检查说话期间的暂停状态，并调用speechSynthesis.resume（）继续。 间隔应足够小，以防止在继续讲话时出现故障。
let timer = null;
let reading = false;
let readText = function(text) {
if (!reading) {
speechSynthesis.cancel();
if (timer) {
clearInterval(timer);
}
let msg = new SpeechSynthesisUtterance();
let voices = window.speechSynthesis.getVoices();
msg.voice = voices[82];
msg.voiceURI = 'native';
msg.volume = 1; // 0 to 1
msg.rate = 1.0; // 0.1 to 10
msg.pitch = 1; //0 to 2
msg.text = text;
msg.lang = 'zh-TW';
msg.onerror = function(e) {
speechSynthesis.cancel();
reading = false;
clearInterval(timer);
};
msg.onpause = function(e) {
console.log('onpause in ' + e.elapsedTime + ' seconds.');
}
msg.onend = function(e) {
console.log('onend in ' + e.elapsedTime + ' seconds.');
reading = false;
clearInterval(timer);
};
speechSynthesis.onerror = function(e) {
console.log('speechSynthesis onerror in ' + e.elapsedTime + ' seconds.');
speechSynthesis.cancel();
reading = false;
clearInterval(timer);
};
speechSynthesis.speak(msg);
timer = setInterval(function(){
if (speechSynthesis.paused) {
console.log("#continue")
speechSynthesis.resume();
}
}, 100);
reading = true;
}
}
答案 10 :(得分：0)
我想说的是，通过Chrome扩展程序和应用程序，我使用chrome.tts解决了这个令人不快的问题，因为chrome.tts允许您通过浏览器讲话，而不是通过阻止讲话的窗口讲话当您关闭窗口时。
使用下面的代码，您可以解决以上问题，并且讲得很清楚：
chrome.tts.speak("Abnormally large string, over 250 characters, etc...");
setInterval(() => { chrome.tts.resume(); }, 100);
我敢肯定这是可行的，但是我这样做是为了安全：
var largeData = "";
var smallChunks = largeData.match(/.{1,250}/g);
for (var chunk of smallChunks) {
chrome.tts.speak(chunk, {'enqueue': true});
}
希望这对某人有帮助！它有助于使my application在功能上更有效地工作，并且在功能上更出色地工作。
答案 11 :(得分：-1)
new Vue({
el: "#app",
data: {
text: `Collaboratively administrate empowered markets via plug-and-play networks. Dynamically procrastinate B2C users after installed base benefits. Dramatically visualize customer directed convergence without revolutionary ROI. Efficiently unleash cross-media information without cross-media value. Quickly maximize timely deliverables for real-time schemas. Dramatically maintain clicks-and-mortar solutions without functional solutions.`
},
methods:{
stop_reading() {
const synth = window.speechSynthesis;
synth.cancel();
},
talk() {
const synth = window.speechSynthesis;
const textInput = this.text;
const utterThis = new SpeechSynthesisUtterance(textInput);
utterThis.pitch = 0;
utterThis.rate = 1;
synth.speak(utterThis);
const resumeInfinity = () => {
window.speechSynthesis.resume();
const timeoutResumeInfinity = setTimeout(resumeInfinity, 1000);
}
utterThis.onstart = () => {
resumeInfinity();
};
}
}
})<script src="https://cdnjs.cloudflare.com/ajax/libs/vue/2.5.17/vue.js"></script>
<div id="app">
<button @click="talk">Speak</button>
<button @click="stop_reading">Stop</button>
</div>