为什么parallel_accumulate更慢?

时间:2014-02-21 14:51:37

标签: c++ multithreading pthreads

我尝试使用gcc / ubuntu在我的8内核计算机上用以下程序测试并行累积和串行累积之间的区别。无论我打开还是关闭优化编译器选项,似乎串行版本总是更快。

class ParalellAccumulator
{
public:
template<typename Iterator, typename T>
struct accumulate_block
{
    void operator()(Iterator first, Iterator last, T& result)
    {
        result = std::accumulate(first, last, result);
    }
};

template<typename Iterator, typename T>
static T parallel_accumulate(Iterator first, Iterator last, T init)
{
    unsigned long const length = std::distance(first, last);
    if (!length)
        return init;

    unsigned long const min_per_thread = 25;
    unsigned long const max_threads = (length + min_per_thread - 1)
            / min_per_thread;

    unsigned long const hardware_threads =
            std::thread::hardware_concurrency();

    unsigned long const num_threads = std::min(
            hardware_threads != 0 ? hardware_threads : 2, max_threads);

    unsigned long const block_size = length / num_threads;

    std::vector<T> results(num_threads);
    std::vector<std::thread> threads(num_threads - 1);

    Iterator block_start = first;
    for (unsigned long i = 0; i < (num_threads - 1); ++i)
    {
        Iterator block_end = block_start;
        std::advance(block_end, block_size);
        threads[i] = std::thread(accumulate_block<Iterator, T>(),
                block_start, block_end, std::ref(results[i]));
        block_start = block_end;
    }
    accumulate_block<Iterator, T>()(block_start, last,
            results[num_threads - 1]);

    std::for_each(threads.begin(), threads.end(),
            std::mem_fn(&std::thread::join));
    return std::accumulate(results.begin(), results.end(), init);

}

static void test()
{
    std::vector<double> rawData(100000000);
    std::cout << "Accumulating " << rawData.size() << std::endl;
    for (size_t i = 0; i < rawData.size(); i++)
    {
        rawData[i] = (double) rand() / RAND_MAX;
        //std::cout << rawData[i] << std::endl;
    }

    clock_t start = clock();
    double result = 0.0;
    result = std::accumulate(begin(rawData), end(rawData), result);
    long diff = clock() - start;
    std::cout << "Serial result: " << result << " in "
            << (double) diff / CLOCKS_PER_SEC << " seconds" << std::endl;

    start = clock();
    result = 0.0;
    result = parallel_accumulate(begin(rawData), end(rawData), result);
    diff = clock() - start;
    std::cout << "Parallel result: " << result << " in "
            << (double) diff / CLOCKS_PER_SEC << " seconds" << std::endl;

}
};

启用优化选项后,结果为:

Accumulating 100000000
Serial result: 5.00011e+07 in 0.09 seconds
Parallel result: 5.00011e+07 in 0.25 seconds

关闭优化选项后,结果为:

Accumulating 100000000
Serial result: 5.00011e+07 in 0.85 seconds
Parallel result: 5.00011e+07 in 1.51 seconds

可能出现什么问题?

0 个答案:

没有答案