Question

我目前有以下代码（它是css和html的混合）用于切换。最终，用户可以切换数据库中的值以从0更改为1.但是，如果没有提交按钮，我不知道如何执行此操作。

CSS：

.onoffswitch {
    position: relative; width: 45px;
    -webkit-user-select:none; -moz-user-select:none; -ms-user-select: none;
}
.onoffswitch-checkbox {
    display: none;
}
.onoffswitch-label {
    display: block; overflow: hidden; cursor: pointer;
    border: 2px solid #E3E3E3; border-radius: 10px;
}
.onoffswitch-inner {
    width: 200%; margin-left: -100%;
    -moz-transition: margin 0.3s ease-in 0s; -webkit-transition: margin 0.3s ease-in 0s;
    -o-transition: margin 0.3s ease-in 0s; transition: margin 0.3s ease-in 0s;
}
.onoffswitch-inner:before, .onoffswitch-inner:after {
    float: left; width: 50%; height: 15px; padding: 0; line-height: 15px;
    font-size: 7px; color: white; font-family: Trebuchet, Arial, sans-serif; font-weight: bold;
    -moz-box-sizing: border-box; -webkit-box-sizing: border-box; box-sizing: border-box;
}
.onoffswitch-inner:before {
    content: "ON";
    padding-left: 5px;
    background-color: #5B969C; color: #EEEEEE;
}
.onoffswitch-inner:after {
    content: "OFF";
    padding-right: 5px;
    background-color: #EEEEEE; color: #5B969C;
    text-align: right;
}
.onoffswitch-switch {
    width: 15px; margin: 0px;
    background: #FFFFFF;
    border: 2px solid #E3E3E3; border-radius: 10px;
    position: absolute; top: 0; bottom: 0; right: 26px;
    -moz-transition: all 0.3s ease-in 0s; -webkit-transition: all 0.3s ease-in 0s;
    -o-transition: all 0.3s ease-in 0s; transition: all 0.3s ease-in 0s; 
}
.onoffswitch-checkbox:checked + .onoffswitch-label .onoffswitch-inner {
    margin-left: 0;
}
.onoffswitch-checkbox:checked + .onoffswitch-label .onoffswitch-switch {
    right: 0px; 
}

HTML：

<div class="onoffswitch">
    <input type="checkbox" name="onoffswitch" class="onoffswitch-checkbox"      id="onoffswitch6">
    <label class="onoffswitch-label" for="onoffswitch6">
        <div class="onoffswitch-inner"></div>
        <div class="onoffswitch-switch"></div>
    </label>
</div>

编辑：在答案之后我将此脚本添加到页面和PHP文件中。但是，它仅在数据库中更改为1，但不会将其更改回0。

脚本：

$(document).ready(function(){
            $('#onoffswitch6').change(function() {
                var checked = $(this).is(':checked'); //true or false?
                $.ajax({
                    type: "post",
                    url: "encrypt.php", //PHP or whichever other language script that updates your database
                    data: { onOrOff : checked } //access this value in your script via $_POST['onOrOff'], if it's a PHP script
                    });
            });
        });

PHP文件：

<?php
//Start session
session_start();

//Include database connection details
require_once('connection.php');

if(isset($_POST['onOrOff']))
{
    if ($_POST['onOrOff'] == false) {
        global $onOrOff;
        $onOrOff = 0;
    } else if ($_POST['onOrOff'] == true) {
        global $onOrOff;
        $onOrOff = 1;
    };

$qry = "UPDATE member SET value='$onOrOff' WHERE id='$_SESSION[SESS_MEMBER_ID]'";
$result = mysql_query($qry) or die("An error occurred ".mysql_error());
}
?>

Answer 1

AJAX就是您所需要的。由于我没有太多信息，我会做一个小例子：

$('.onoffswitch-checkbox').change(function() {
    var checked = $(this).is(':checked'); //true or false?
    $.ajax({
        type: "post",
        url: "myscript.php", //PHP or whichever other language script that updates your database
        data: { onOrOff : checked } //access this value in your script via $_POST['onOrOff'], if it's a PHP script
    });
});

使用复选框更新MySQL值

1 个答案: