Question

from multiprocessing import Process , Queue
from datetime import datetime

c = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27]
out = Queue()
def support(m):
    for k in m :
        print "%s <-- hi" % k
    out.put("done")

all = Queue()
temp = []
total = len(c)
count = 0
for m in c :
        count += 1
        total = total - 1
        temp.append(m)
        if count == 5 or total == 0 :
                all.put(temp)
                count = 0
                temp = []

process_count = 3

while all.qsize() != 0 :
    process_list = []
    try :
        for x in range(process_count) :
            p = Process(target=support, args=(all.get(),))
            process_list.append(p)

        for p in process_list :
            p.start()
        for p in process_list :
            p.join()        
    except Exception as e :
       print e

while out.qsize != 0 :
    print out.get()


print "all done"

我不知道为什么它没有结束并且不打印“全部完成”，只是保持连续循环或继续执行。如果你可以使这个代码更有效率，但首先我想知道为什么它不会结束，将会有很大的帮助。

Answer 1

问题是：

while out.qsize != 0 :
    print out.get()

out.qsize是一个函数，所以现在你将函数本身（不是返回值！）与0进行比较，当然总是False。

您应该使用：

while out.qsize() != 0 :
    print out.get()

Python多处理，代码继续执行？

1 个答案: