Question

当有人在我的网页上填写表单时，我正在尝试向自己发送电子邮件。我的表格如下：

    <form id="contactForm" action="#" method="post">
                <fieldset>                      
                    <p>
                        <label for="name" >Name</label>
                        <input name="name"  id="name" type="text" class="form-poshytip" title="Enter your full name" />
                    </p>
                    <p>
                        <label for="email" >Email</label>
                        <input name="email"  id="email" type="text" class="form-poshytip" title="Enter your email address" />
                    </p>
                    <p>
                        <label for="web">Website</label>
                        <input name="web"  id="web" type="text" class="form-poshytip" title="Enter your website" />
                    </p>
                    <p>
                        <label for="comments">Message</label>
                        <textarea  name="comments"  id="comments" rows="5" cols="20" class="form-poshytip" title="Enter your comments"></textarea>
                    </p>
                    <!-- send mail configuration -->
                    <input type="hidden" value=EMAIL" name="to" id="to" />
                    <input type="hidden" value="Email received from Website" name="subject" id="subject" />
                    <input type="hidden" value="send-mail.php" name="sendMailUrl" id="sendMailUrl" />
                    <!-- ENDS send mail configuration -->

                    <p><input type="button" value="Send" name="submit" id="submit" /> <span id="error" class="warning">Message</span></p>
                </fieldset>

            </form>

和PHP我看起来像这样：

<?php
//vars
$subject = $_POST['subject'];
$to = explode(',', $_POST['to'] );

$from = $_POST['email'];

//data
$msg = "NAME: "  .$_POST['name']    ."<br>\n";
$msg .= "EMAIL: "  .$_POST['email']    ."<br>\n";
$msg .= "WEBSITE: "  .$_POST['web']    ."<br>\n";
$msg .= "COMMENTS: "  .$_POST['comments']    ."<br>\n";

//Headers
$headers  = "MIME-Version: 1.0\r\n";
$headers .= "Content-type: text/html; charset=UTF-8\r\n";
$headers .= "From: <".$from. ">" ;

$smtp = Mail::factory('smtp', array(
        'host' => 'ssl://smtp.gmail.com',
        'port' => '465',
        'auth' => true,
        'username' => 'EMAIL',
        'password' => 'PASSWORD'
    ));

$mail = $smtp->send($to, $headers, $msg);
?>

EMAIL和PASSWORD被替换为值....

有人可以建议做什么吗？

Answer 1

将主机更新为smtp.gmail.com并将端口更新为587并使用结果更新我们。

Answer 2

编辑（一体化）

PHP - 和HTML一起（并用您自己的SMTP替换mail()函数）

I.e。：

$mail = $smtp->send($to, $subject, $msg, $headers);

新代码：

<?php
//vars

if(isset($_POST['submit'])){
$subject = $_POST['subject'];

$to = "email@example.com";

$from = $_POST['email'];

//data
$msg = "NAME: "  .$_POST['name']    ."<br>\n";
$msg .= "EMAIL: "  .$_POST['email']    ."<br>\n";
$msg .= "WEBSITE: "  .$_POST['web']    ."<br>\n";
$msg .= "COMMENTS: "  .$_POST['comments']    ."<br>\n";

//Headers
$headers  = "MIME-Version: 1.0\r\n";
$headers .= "Content-type: text/html; charset=UTF-8\r\n";
$headers .= "From: <".$from. ">" ;

// insert with your SMTP

mail ($to, $subject,$msg, $headers); 
echo "sent";
}
?>


<form id="contactForm" action="" method="post">
    <fieldset>                      
        <p>
            <label for="name" >Name</label>
            <input name="name"  id="name" type="text" class="form-poshytip" title="Enter your full name" />
        </p>
        <p>
            <label for="email" >Email</label>
            <input name="email"  id="email" type="text" class="form-poshytip" title="Enter your email address" />
        </p>
        <p>
            <label for="web">Website</label>
            <input name="web"  id="web" type="text" class="form-poshytip" title="Enter your website" />
        </p>
        <p>
            <label for="comments">Message</label>
            <textarea  name="comments"  id="comments" rows="5" cols="20" class="form-poshytip" title="Enter your comments"></textarea>
        </p>
        <!-- send mail configuration -->
        <input type="hidden" value="Email received from Website" name="subject" id="subject" />

        <!-- ENDS send mail configuration -->

        <p><input type="submit" value="Send" name="submit" id="submit" /> <span id="error" class="warning">Message</span></p>
    </fieldset>

</form>

原始答案

您的代码存在很多问题。

您的参数已关闭($to, $headers, $msg)标题位于最后且$subject未包括在内;它必须在那里。

语法为($to, $subject,$msg, $headers)

它是TO，然后是Subject，然后是Message，然后是Headers。根据{{3}}即使您使用SMTP， 邮件也是邮件。

我不知道你为什么这么做：

<input type="hidden" value="send-mail.php" name="sendMailUrl" id="sendMailUrl" />

只需在表单action=

中设置即可

这对我有用：你可以替换：

mail ($to, $subject, $msg, $headers);

with（如果它适用于你）似乎还有其他答案。

$smtp = Mail::factory('smtp', array(
        'host' => 'ssl://smtp.gmail.com',
        'port' => '465',
        'auth' => true,
        'username' => 'EMAIL',
        'password' => 'PASSWORD'
    ));

$mail = $smtp->send($to, $headers, $msg);

PHP - 经过测试（send-mail.php）

<?php
//vars

if(isset($_POST['submit'])){
$subject = $_POST['subject'];

$to = "email@example.com";

$from = $_POST['email'];

//data
$msg = "NAME: "  .$_POST['name']    ."<br>\n";
$msg .= "EMAIL: "  .$_POST['email']    ."<br>\n";
$msg .= "WEBSITE: "  .$_POST['web']    ."<br>\n";
$msg .= "COMMENTS: "  .$_POST['comments']    ."<br>\n";

//Headers
$headers  = "MIME-Version: 1.0\r\n";
$headers .= "Content-type: text/html; charset=UTF-8\r\n";
$headers .= "From: <".$from. ">" ;

mail ($to, $subject,$msg, $headers);
echo "sent";
}
?>

HTML表单

<form id="contactForm" action="send-mail.php" method="post">
    <fieldset>                      
        <p>
            <label for="name" >Name</label>
            <input name="name"  id="name" type="text" class="form-poshytip" title="Enter your full name" />
        </p>
        <p>
            <label for="email" >Email</label>
            <input name="email"  id="email" type="text" class="form-poshytip" title="Enter your email address" />
        </p>
        <p>
            <label for="web">Website</label>
            <input name="web"  id="web" type="text" class="form-poshytip" title="Enter your website" />
        </p>
        <p>
            <label for="comments">Message</label>
            <textarea  name="comments"  id="comments" rows="5" cols="20" class="form-poshytip" title="Enter your comments"></textarea>
        </p>
        <!-- send mail configuration -->
        <input type="hidden" value="Email received from Website" name="subject" id="subject" />

        <!-- ENDS send mail configuration -->

        <p><input type="submit" value="Send" name="submit" id="submit" /> <span id="error" class="warning">Message</span></p>
    </fieldset>

</form>

<强>脚注：

value=EMAIL"中缺少引号，但我的PHP已将其替换为：

$to = "email@example.com";

Answer 3

这是一种便宜而简单的方法。

在你的php.ini中用

替换邮件功能的相关部分

[mail function]
; For Win32 only.
SMTP = smtp.gmail.com
smtp_port = 587

; For Win32 only.
sendmail_from = EMAILADDRESSHERE

用

替换sendmail.ini

[sendmail] 
smtp_server=smtp.gmail.com

smtp_port=587

error_logfile=error.log

auth_username=EMAILADDRESSHERE
auth_password=PASSWORDHERE

force_sender=EMAILADDRESSHERE

然后在您的代码中，发送一封相同的电子邮件，除非将其写为

 mail($to, $subject, $msg, $headers)

或修改以适应。

Answer 4

您必须首先检查变量$ to的值是否是正确的邮件方向。基于您发布的代码可能会出错。

在PHP代码中，您调用类Mail但不包含/ require，添加：

// Pear Mail Library
require_once "Mail.php";

发送邮件后，您无法显示结果：

if (PEAR::isError($mail)) {
    echo('<p>' . $mail->getMessage() . '</p>');
} else {
    echo('<p>Message successfully sent!</p>');
}

Answer 5

首先，检查邮箱中的垃圾邮件。如果gmail收到了你的邮件，它必须在那里。如果没有，请检查您的邮件服务器配置以及是否有权为您的域发送邮件。您还可以检查邮件服务器日志中是否存在潜在问题。

无论如何，我建议您使用Mailjet或MailChimp等解决方案。您可以注册基本套餐并收到电子邮件。这样的解决方案的优点是您不需要维护您的邮件服务器，您可以检查每个正在处理的邮件的状态。

PHP / HTML表单数据将作为电子邮件从我的GMAIL帐户发送

5 个答案:

编辑（一体化）

原始答案