Question

<segmentFlightRef>
    <referencingDetail>
         <refQualifier>S</refQualifier> 
         <refNumber>4</refNumber> 
    </referencingDetail>
    <referencingDetail>
        <refQualifier>S</refQualifier> 
        <refNumber>1</refNumber> 
    </referencingDetail>
</segmentFlightRef>
<segmentFlightRef>
    <referencingDetail>
        <refQualifier>S</refQualifier> 
        <refNumber>5</refNumber> 
    </referencingDetail>
    <referencingDetail>
        <refQualifier>S</refQualifier> 
        <refNumber>1</refNumber> 
    </referencingDetail>
</segmentFlightRef>
  <segmentFlightRef>
    <referencingDetail>
        <refQualifier>S</refQualifier> 
        <refNumber>1</refNumber> 
    </referencingDetail>
    <referencingDetail>
        <refQualifier>S</refQualifier> 
        <refNumber>5</refNumber> 
    </referencingDetail>
</segmentFlightRef>

在上面的xml中我想要“segmentFlightRef”标签，其子节点“refNumber”的值为“5”和“1”。必须考虑和序列，所以我只需要一个节点的子节点值为5和1的节点请帮我提前致谢

Answer 1

XPath ：

//segmentFlightRef[./referencingDetail[./refNumber[text()="5"] and ./following-sibling::referencingDetail[./refNumber[text()="1"]]]]

解释：

//segmentFlightRef[./referencingDetail[...]]

选择具有子元素<segmentFlightRef>的{{1}}元素，条件如下：

标准我：

<referencingDetail>

让子元素./refNumber[text()="5"]的内部文字等于<refNumber>。

标准II ：

"5"

并且具有条件的下一个/同级节点and ./following-sibling::referencingDetail[./refNumber[text()="1"]]：具有内部文本等于<referencingDetail>的子元素<refNumber>。

Answer 2

的XPath：

//segmentFlightRef[referencingDetail[following-sibling::referencingDetail/refNumber = 1]/refNumber = 5]

使用xpath选择特定的xnode

2 个答案: