Question

当我自己运行应用程序时，没有这样的行为 - 一旦AsyncTask完成执行，它就会返回到我的MainActivity（从第一位开始AsyncTask）。

但是，在我的测试用例中，当AsyncTask刚刚开始执行一小段时间时，MainActivity突然暂停，停止和销毁。

如何确保活动等待AsyncTask将其回拨，就像我的应用程序的行为方式一样？

02-21 17:23:13.063: W/MainActivity(16685): onCreate
02-21 17:23:13.133: W/MainActivity(16685): refreshRequired
02-21 17:23:13.233: W/MainActivity(16685): user is not regitered

02-21 17:23:13.233: W/MainActivity(16685): onStart
02-21 17:23:13.233: W/MainActivity(16685): onResume
02-21 17:23:16.686: W/MainActivityFunctionalTest(16685): performing the button click action
02-21 17:23:17.227: W/MainActivity(16685): Submit button is clicked
02-21 17:23:17.377: W/Process(16685): doInBackground

02-21 17:23:17.377: W/RegistrationManager(16685): doRegistration
02-21 17:23:17.387: W/RegistrationManager(16685): sendJobRequest
02-21 17:23:17.487: W/RegistrationManager(16685): didOpenedAPDUConnection
02-21 17:23:17.507: W/MainActivity(16685): onPause
02-21 17:23:17.617: W/RegistrationManager(16685): sending HTTP request
02-21 17:23:17.617: W/MessageProcessor(16685): sending a HTTP request
02-21 17:23:17.627: W/HTTPRequest(16685): HTTPRequest.startAsynchronous timeout : 60000
02-21 17:23:17.627: W/HTTPRequest(16685): url is: ...
02-21 17:23:17.848: W/HTTPRequest(16685): HTTPRequest.readResponse RESP BODY = ca000000250104313030350218437573746f6d657220646f6573206e6f74206578697374210900000000
02-21 17:23:17.848: W/MessageProcessor(16685): requestFinished
02-21 17:23:17.858: W/RegistrationManager(16685): didFailedJobRequestWithResponseMsg
02-21 17:23:17.898: W/Process(16685): onPostExecute
02-21 17:38:29.057: W/MainActivity(17483): onStop
02-21 17:38:29.057: W/MainActivity(17483): onDestroy

我的测试班：

public class MainActivityFunctionalTest extends
        ActivityInstrumentationTestCase2<MainActivity> {
public void testRegistrationFormIsSubmitted() {
        final MainActivity mainActivity = (MainActivity) solo
                .getCurrentActivity();
        solo.assertCurrentActivity("current activity not main activity",
                MainActivity.class);
final View submitBtn = solo.getView(R.id.btn_next);

        assertNotNull(submitBtn);

        Log.w(TAG, "performing the button click action");

                    solo.clickOnView(submitBtn);
}
}

MainActivity

ImageButton submitBtn = (ImageButton) findViewById(R.id.btn_next);
        submitBtn.setImageResource(R.drawable.btn_submit);
        // View submitBtn = findViewById(R.id.btn_next);

        submitBtn.setOnClickListener(new OnClickListener() {
            public void onClick(View v) {
                Log.w(TAG, "Submit button is clicked");
                sendActivation(v);
            }
        }); 
private void sendActivation(View v) {

        process = new Processor(this, this.getApplicationContext());

        process.execute();
    }

Processor.java

public class Processor extends AsyncTask<Void, String, Void>{
    @Override
    protected Void doInBackground(Void... arg0)
    {


        Log.w(TAG, "doInBackground");
        mManager.doRegistration();
        return null;
}

}

Answer 1

protected Void doInBackground(Void... arg0)你不应该做任何UI更改，甚至不显示Toasts它会引发错误。

所以mManager.doRegistration();如果你正在执行任何UI更改，它将抛出错误，

相反，如果有任何UI更改，您可以在protected void onPostExecute()中使用它。

Android测试 - 在执行AsyncTask时意外销毁Activity

1 个答案: