如何在点击上传按钮后立即显示图片?
这是我的HTML代码:
form.php的
<html>
<body>
<form action="uploadFile.php" method="post" enctype="multipart/form-data">
<label for="file">Filename:</label>
<input type="file" name="file" id="file"><br>
<input type="submit" name="submit" value="Submit">
</form>
</body>
</html>
这是我的uploadFile.php代码:(已更新,但仍未获得任何结果)
<?php
// prevent timezone warnings
date_default_timezone_set('Philippines/Manila');
// set the upload location
$UPLOADDIR = "images/";
// if the form has been submitted then save and display the image(s)
if(isset($_POST['Submit'])){
// loop through the uploaded files
foreach ($_FILES as $key => $value){
$image_tmp = $value['tmp_name'];
$image_type=$value['type'];
$image = $value['name'];
$image_file = "{$UPLOADDIR}{$image}";
//check if there's existing file name
if ($image != 0){
echo 'File Already Exists!';
}
else {
// move the file to the permanent location
if(move_uploaded_file($image_tmp,$image_file)){
// this is where the displaying part goes
echo <<<HEREDOC
<div style="float:left;margin-right:10px">
<img src="$editedShear" alt="This is your image" height=200 width=200/></br>
</div>
HEREDOC;
}
else{
echo "<h1>image file upload failed, image too big after compression</h1>";
}
}
}}
else{
?>
<?php
}
?>
答案 0 :(得分:0)
为此,您需要使用某种ajax上传来上传图像。如果你不知道那是什么,请在这里阅读http://en.wikipedia.org/wiki/Ajax_%28programming%29。您可以在线找到一些免费的解决方案和示例。在这里,我发现了一个堆栈溢出问题,可能会帮助您链接到这样的解决方案
答案 1 :(得分:0)
在表单后添加iframe
:
<iframe name="resultFrame" width="500" height="300"></iframe>
并在表单中添加target="resultFrame"
属性,如下所示:
<html>
<body>
<form action="uploadFile.php" method="post"
enctype="multipart/form-data" target="resultFrame">
<label for="file">Filename:</label>
<input type="file" name="file" id="file"><br>
<input type="submit" name="submit" value="Submit">
</form>
<iframe name="resultFrame" width="500" height="300"></iframe>
</body>
</html>
答案 2 :(得分:0)
将图片上传到包含php / html文件的文件夹中, 并在img标签中写入img名称:
<img src="<?php echo $img;?>" width="400" height="600"/>
答案 3 :(得分:0)
/* i put image so that it has default
<img id="blah" src="images/male.png" alt="your image" style="width:250px;height:200px;" />
/*put accept and its format so that you can only choose the image only
<input type='file' name="image" onchange="readURL(this);" accept="image/gif,image/png,image/jpg,image/jpeg" />
/*changing the url of an image you can do it in jquery
function readURL(input) {
if (input.files && input.files[0]) {
var reader = new FileReader();
reader.onload = function (e) {
$('#blah')
.attr('src', e.target.result)
/*set the width and height of an image
.width(250)
.height(200);
};
reader.readAsDataURL(input.files[0]);
}
}
之后执行上传代码
答案 4 :(得分:0)
上传图片并在同一页面上显示上传图片的最简单方法是什么? page&#34; index.php&#34;
<body>
<div id="body">
<form action="upload.php" name="img_compress" method="post" enctype="multipart/form-data">
<input type="file" name="file" />
<button type="submit" name="btn-upload">upload</button>
</form>
<br /><br />
<?php
if(isset($_GET['success']))
{
?><br><br><br>
<?php
$sql="SELECT * FROM tbl_uploads ORDER BY id DESC";
$result_set=mysql_query($sql);
while($row=mysql_fetch_array($result_set))
{
?>
<img src="uploads/<?php echo $row['file'] ?>" width="100%" height="100%">
<?php
}
?>
<?php
}
else if(isset($_GET['fail']))
{
?>
<label>Problem While File Uploading !</label>
<?php
}
else
{
?>
<label>Try to upload any files(PDF, DOC, EXE, VIDEO, MP3, ZIP,etc...)</label>
<?php
}
?>
</div>
</body>
&#13;
上传代码&#34; upload.php&#34;
<?php
include_once 'dbconfig.php';
if(isset($_POST['btn-upload']))
{
$file = $_FILES['file']['name'];
$file_loc = $_FILES['file']['tmp_name'];
$file_size = $_FILES['file']['size'];
$file_type = $_FILES['file']['type'];
$folder="uploads/";
$new_size = $file_size/1024;
$new_file_name = strtolower($file);
$final_file=str_replace(' ','-',$new_file_name);
if(move_uploaded_file($file_loc,$folder.$final_file))
{
$sql="INSERT INTO tbl_uploads(file,type,size) VALUES('$final_file','$file_type','$new_size')";
mysql_query($sql);
?>
<script>
window.location.href='index.php?success';
</script>
<?php
}
else
{
?>
<script>
alert('error while uploading file');
window.location.href='index.php?fail';
</script>
<?php
}
}
?>
&#13;