Question

我是iOS编程新手。我正在尝试在我的应用程序中验证用户。我在android中完成了这个，没有使用JSON的任何问题。我想在这里做同样的事情。我看过this并将代码应用到我的应用中，但我收到此错误：

There was an error processing the request

以下是我从网址检索JSON的完整代码：

-(NSString*) getjsonFromURl:(NSURL*)url :(NSArray*) key : (NSArray*)value;
{
    NSDictionary *jsonDictionary = [NSDictionary dictionaryWithObjects:value forKeys:key];

    if([NSJSONSerialization isValidJSONObject:jsonDictionary])
    {
        __jsonData = [NSJSONSerialization dataWithJSONObject:jsonDictionary options:0 error:nil];
        __jsonString = [[NSString alloc]initWithData:__jsonData encoding:NSUTF8StringEncoding];
    }

    // Be sure to properly escape your url string.

    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
    [request setHTTPMethod:@"POST"];
    [request setHTTPBody: __jsonData];
    [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
    [request setValue:[NSString stringWithFormat:@"%d", [__jsonData length]] forHTTPHeaderField:@"Content-Length"];

    NSError *errorReturned = nil;
    NSURLResponse *theResponse =[[NSURLResponse alloc]init];
    NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&theResponse error:&errorReturned];

    if (errorReturned)
    {
        NSLog(@"Error %@", errorReturned);
    }
    else
    {
         responseString=[NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers|NSJSONReadingAllowFragments error:nil];
        NSLog(@"%@", responseString);
    }
    return responseString;
}

我不知道错误在哪里。我也会发布我的安卓代码[因为在这里我想和我做的完全一样]

public JSONObject getJSONFromUrl(JSONObject parm,String url) throws JSONException
{
    InputStream is = null;
    JSONObject jObj = null;
    String json = "";

    // Making HTTP request
    try 
    {
        // defaultHttpClient
        /*JSONObject parm = new JSONObject();
          parm.put("agencyId", 27);
          parm.put("caregiverPersonId", 47);*/

        /* if(!(jObj.isNull("d"))){
            jObj=null;
            }
        */

        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost httpPost = new HttpPost(url);

        httpPost.addHeader("Content-Type", "application/json; charset=utf-8");
        HttpEntity body = new StringEntity(parm.toString(), "utf8");
        httpPost.setEntity(body);
        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();
        is = httpEntity.getContent();          
    } 
    catch (UnsupportedEncodingException e)
    {
        e.printStackTrace();
    } 
    catch (ClientProtocolException e)
    {
        e.printStackTrace();
    } catch (IOException e)
    {
        e.printStackTrace();
    }

    try
    {
        BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;

        while ((line = reader.readLine()) != null)
        {
            sb.append(line + "\n");
        }

        is.close();
        json = sb.toString();

    }
    catch (Exception e)
    {
        Log.e("Buffer Error", "Error converting result " + e.toString());
    }

    // try parse the string to a JSON object
    try
    {
        jObj = new JSONObject(json);
    } 
    catch (JSONException e)
    {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    }

    // return JSON String
    return jObj;
}

Answer 1

我认为“处理请求时出错”可能是由.NET服务器发送的？如果我错了，请原谅我。

这会让我相信请求存在问题。

您的问题中没有足够的信息可以准确地告诉您哪些是错的，但这是我将如何解决它。

使用您正在运行的Android应用中的所有HTTP标头记录完整请求。然后从你的非工作iOS应用程序做同样的事情。比较这两个请求，你会看到一个区别。消除差异，它将起作用。

对于iOS，我会使用AFNetworking（https://github.com/AFNetworking/AFNetworking）和https://github.com/AFNetworking/AFNetworkActivityLogger来获取标头信息。使用该库可能会解决问题，因为它将为您完成大部分JSON转换。

解决问题的最快方法是比较工作和非工作请求。

将Json对象传递给IOS中的方法

1 个答案: