Question

我是SQL的初学者，我需要帮助来获得这种情况的解决方案。

对于每个景点，输出2013年访问此景点的人数。

create table visitor( 
visitID         char(n),
name            char(n) not null,
primary key (visitID)
);

create table ticket(
ticketID        char(n),
ticketType      char(n),
day             int(n),
month           char(n),
year            int(n),
seasonID        char(n),
visitID         char(n),
primary key (ticketID), foreign key (seasonID) references seasonPerClass, foreign      
key (visitID) references visitor
);

create table attractionVisit(
attractionID        char(n),
ticketID        char(n),
foreign key (attractionID) references attraction, foreign key (ticketID) references    
ticket
);

create table attraction(
attractionID        char(n),
attractionName  char(n) not null,
primary key (attractionID)
);

我无法测试我的代码，但到目前为止我已经

了

SELECT AttractionName, count(distinct VisitID)
FROM (Visitation NATURAL JOIN AttractionVisit)
WHERE year = 2013;

我不知道这是否正确。请帮忙。

Answer 1

您的查询中需要group by：

SELECT AttractionName, count(distinct VisitID)
FROM (Visitation NATURAL JOIN AttractionVisit)
GROUP BY AttractionName
WHERE year = 2013;

Answer 2

select att.attractionName, count(att.attractionId) as count
from visitor v inner join ticket t on ( v.visitID = t.visitID)
inner join attractionVisit av on (t.ticketID = av.ticketID)
inner join attraction att on (av.attractionID = att.attractionID)
where t.year = 2013
group by att.attractionName`

希望这是有帮助的。

用条件计数的SQL语句

2 个答案: