Question

如何从文件中读取浮点数？

  0.00000E+00  2.12863E-01
  1.00000E-02  2.16248E-01
  2.00000E-02  2.19634E-01

在第一列数字之前和数字之间的2个空格中的文件。我有错误：

s = new Scanner(new File("P0"));
while (s.hasNext()) {
    float x = s.nextFloat();
    float y = s.nextFloat();

    System.out.println("x = " + x + ", y = " + y);
}

Answer 1

逐行阅读文件。
根据空格将每一行拆分为单词。
将每个单词转换为浮动。

以下是代码：

    BufferedReader reader = null;

    try {
        // use buffered reader to read line by line
        reader = new BufferedReader(new InputStreamReader(new FileInputStream(new File(
                "<FULL_FILE_PATH>"))));

        float x, y;
        String line = null;
        String[] numbers = null;
        // read line by line till end of file
        while ((line = reader.readLine()) != null) {
            // split each line based on regular expression having
            // "any digit followed by one or more spaces".

            numbers = line.split("\\d\\s+");

            x = Float.valueOf(numbers[0].trim());
            y = Float.valueOf(numbers[1].trim());

            System.out.println("x:" + x + " y:" + y);
        }
    } catch (IOException e) {
        System.err.println("Exception:" + e.toString());
    } finally {
        if (reader != null) {
            try {
                reader.close();
            } catch (IOException e) {
                System.err.println("Exception:" + e.toString());
            }
        }
    }

Answer 2

所以，我理解我的错误。我需要使用

s.useLocale(Locale.US);

因为扫描仪互相干扰＆＃34;。＆＃34;作为小数点分隔符，在我的语言环境中（默认）它是＆＃34;，＆＃34;。另请注意，nextDouble

可识别1.1和3（整数）

//根据this link

从文件中读取浮点数

2 个答案: