Question

我正在尝试发送用户并传递给asp webservice，但是当回复响应时会这样：

所以如何修复它并使其成为假的

这是我用过的网络服务链接：

http://ictfox.com/demo/Hafil_Updates/Login_Check.aspx?UserLogin=Demo&Password=Demo 


02-20 19:57:23.326: D/Http Response:(4007): True<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><title></title></head><body>    <form name="form1" method="post" action="Login_Check.aspx?UserLogin=Demo&amp;Password=Demo" id="form1"><input type="hidden" name="__VIEWSTATE" id="__VIEWSTATE" value="/wEPDwULLTE2MTY2ODcyMjlkZD/N053U40olll80mNvY/Qt2aBEc" />    <div>        </div>    </form></body></html>

这是我在asyncTask android中的全班：

    HttpClient httpClient = new DefaultHttpClient();
    // Creating HTTP Post
    HttpPost httpPost = new HttpPost(
            "http://ictfox.com/demo/Hafil_Updates/Login_Check.aspx?UserLogin=Demo&Password=Demo");

    // Building post parameters
    // key and value pair
    List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>(2);
    nameValuePair.add(new BasicNameValuePair("UserLogin", "Demo"));
    nameValuePair.add(new BasicNameValuePair("Password",
            "Demo"));

    // Url Encoding the POST parameters
    try {
        httpPost.setEntity(new UrlEncodedFormEntity(nameValuePair));
    } catch (UnsupportedEncodingException e) {
        // writing error to Log
        e.printStackTrace();
    }

    // Making HTTP Request
    try {
        HttpResponse response = httpClient.execute(httpPost);

        response.getEntity().getContentLength(); 


        StringBuilder sb = new StringBuilder();
        try {
            BufferedReader reader = 
                   new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
            String line = null;

            while ((line = reader.readLine()) != null) {
                sb.append(line);
            }
        }
        catch (IOException e) { e.printStackTrace(); }
        catch (Exception e) { e.printStackTrace(); }
        Log.d("Http Response:", sb.toString());

Answer 1

是您或3dr派对的网络服务吗？它似乎不仅返回实际的返回值，还返回一些隐藏的HTML内容。检查是否有选项以只返回所需值或甚至更好的JSON的方式调用服务。如果没有，只需检查返回String是否以“True”

开头

boolean success = sb.toString().toLowerCase().startsWith("true");

Answer 2

您需要修改服务器发送的响应，这是最简单的事情。我看到你的服务器返回True后跟一些HTML代码。让您的服务器删除HTML

如果您不想修改服务器端代码，只需查看子串True的响应即可。

此外，为了获得响应，我使用了这个，这可能更简单：

httpresponse = httpclient.execute(httppost);
response = EntityUtils.toString(httpresponse.getEntity());

调用asp web服务不能正常工作

2 个答案: