Question

我在.bat文件中包含此脚本，并希望仅在文件末尾保留最近的100行。

如何删除所有其他行？

@echo off  
REM *DATETIME2.BAT 
REM *Copy date and time to create a new log file 
echo.|date>>"\\spserver\myfolder\dt.tmp" 
echo.|time>>"\\spserver\myfolder\dt.tmp"   
IF NOT EXIST "\\spserver\myfolder\dt.tmp" GOTO Error1 
type "\\spserver\myfolder\dt.tmp"|FIND "current">"\\spserver\myfolder\dt.log" 
rem del "\\spserver\myfolder\dt.tmp"
GOTO End 

:Error1 
Echo.  
Echo There was an error processing the command.  
Echo Unable to find temporary sort file DATETIME2.TMP.  
Echo.  
GOTO End 

:End

Answer 1

你走了：

Call :Tail 100 dt.log tempout.txt
move /y tempout.txt dt.log>nul
exit /b

:Tail <numlines> <FileIn> <FileOut> 
FOR /F "usebackq tokens=3,3 delims= " %%l IN (
  `find /c /v "" %2`) DO (call SET find_lc=%%l)
SET /a linenumber=%find_lc%-%1
IF %linenumber% LSS 1 (
  more +0 %2 >> %3
) ELSE (
  more +%linenumber% %2 >> %3
)

在文本文件中保留最后100行数据

1 个答案: