Question

我想把我的getText的scrapBookId放在textview上，我能够干杯并返回值，但是一旦我把它放到textview中就没有价值，有人可以帮我吗？谢谢

protected void onCreate(Bundle savedInstanceState) {
        // TODO Auto-generated method stub
        super.onCreate(savedInstanceState);
        setContentView(R.layout.upload);
        addListenerOnButton();

        userid = (TextView) findViewById(R.id.userid);
        spinner = (Spinner) findViewById(R.id.spinnerscrapbookid);
        sbid = (TextView)findViewById(R.id.scrapbook_id);

        spinner.setOnItemSelectedListener(new OnItemSelectedListener() {
            @Override
            public void onItemSelected(AdapterView<?> parent, View view,
                    int position, long id) {
                // ---getting values from selected Spinner
                scrapBookId = ((TextView) view.findViewById(R.id.scrapBookId)).getText().toString();

                Toast.makeText(getApplicationContext(), "" + scrapBookId, Toast.LENGTH_SHORT).show();

            }

            @Override
            public void onNothingSelected(AdapterView<?> arg0) {

            }
        });
        sbid.setText(scrapBookId);

        //---HashMap for SpinnerView
        scrapBookList = new ArrayList<HashMap<String, String>>();

        SharedPreferences sp = PreferenceManager
                .getDefaultSharedPreferences(this);
        userid.setText(sp.getString("user_id", null));

        imageview = (ImageView) findViewById(R.id.imageView);
        new LoadAllScrapBook().execute();
    }

Answer 1

您还必须将该行放入OnItemSelectedListener：

sbid.setText(scrapBookId);

正如您现在所做的那样，您在用户选择了任何内容之前在TextView 中显示了ID，因此您当然会看到您初始化的值scrapBooxId用。

我将如何在textview上显示我getText（）的字符串

1 个答案: