Question

我无法让我的验证（表单）函数在我的ajax函数之前运行。任何有关如何将两者结合在一起并在提交表单时按顺序运行的建议将是最有帮助的。谢谢！

    <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js"></script>
    <script type="text/javascript" src="includes/JSValidation.js"></script>
    <script type="text/javascript">


     // These first three lines of code compensate for Javascript being turned on and off. 
    // It simply changes the submit input field from a type of "submit" to a type of "button".

var paraTag = $('input#submit').parent('p');
$(paraTag).children('input').remove();
$(paraTag).append('<input type="button" name="submit" id="submit" value="Contact Us!" />');

    $(function() {
$('#contactForm input#submit').click(function() {
$('#contactForm').append('<img src="ajax-loader.gif" class="loaderIcon" alt="Loading..." />');
        var firstname = $('input#firstname').val();
        var lastname = $('input#lastname').val();
        var email = $('input#email').val();
        var message = $('textarea#message').val();

        $.ajax({
            type: 'post',
            url: 'email.php',
            data: 'firstname=' + firstname + '&lastname=' + lastname + '&email=' + email + '&message=' + message,

            success: function(results) {
                $('#contactform img.loaderIcon').fadeOut(1000);
                    $('td#response').html(results);
            }
        }); //end ajax
});
 });



 //Validation
 function validate(form){
var firstName = form.firstname.value;
var lastName = form.lastname.value;
var email = form.email.value;
var subject = form.subject.value;
var message = form.message.value;
var errors = [];

if (!reProperName.test(firstName)) {
    errors[errors.length] = "You must enter a valid first name.";
}

if (!reProperName.test(lastName)) {
    errors[errors.length] = "You must enter a valid last name.";
}

if (!reEmail.test(email)) {
    errors[errors.length] = "You must enter a valid email address.";
}

if (checkTextArea(message,1000)) {
    errors[errors.length] = "Your message is too long.  It must be less than 100 characters.";
}

if (errors.length > 0) {
    reportErrors(errors);
    return false;
}
submitForm(contactForm);
return true;

 }

 function reportErrors(errors){
var msg = "There were some problems...\n";
for (var i = 0; i<errors.length; i++) {
    var numError = i + 1;
    msg += "\n" + numError + ". " + errors[i];
}
alert(msg);
 }
 </script>
 </head>
 <body>
 <div id="wrap">
 <?php
 require 'includes/header.php';
 ?>
<div id="main">
    <h1 align="center">Contact Form:</h1>
    <div>
        <form method="post" id="contactForm" autocomplete="on" onclick="return validate(this);"  action="includes/email.php">
         <table width="350" border="0" align="center" cellpadding="4" cellspacing="0">
          <tr> 
            <td><label>Your First Name:</label></td>
            <td><input type="text" name="firstname" id="firstname" style="width:100%" />     </td>
          </tr>
          <tr> 
            <td><label>Your Last Name:</label></td>
            <td><input type="text" name="lastname" id="lastname" style="width:100%" /></td>
          </tr>
          <tr> 
            <td><label>Your Email:</label></td>
            <td><input type="text" name="email" id="email" style="width:100%" /></td>
          </tr>
          <tr> 
            <td colspan="2">
                <label>Your Message:</label><br /><br />
                <textarea name="message" style="width:100%;height:160px" id="message"></textarea>
            </td>
          </tr>
          <tr align="center"> 
            <td colspan="2"><input type="submit" name="submit" value="Contact Us!" id="submit"></td>
          </tr>
          <tr align="center">
            <td colspan="2" id="response" />
          </tr>
        </table>

        </form> 
     </div>                  

 <div class="push" />
 </div>
 <?php
  require 'includes/footer.php';
 ?>
 </body>

Answer 1

更改验证功能，如下所示，

function validate() {
    var firstName = $("#firstname").val();
    var lastName = $("#lastname").val();
    var email = $("#email").val();
    var subject = $("#subject").val();
    var message = $("#message").val();

    ***************
}

并更改jQuery事件，

$(function () {
    $('#contactForm #submit').click(function (e) {
        e.preventDefault();
        if (validate()) {
            // Ajax code
        }else{
            // not valid
        }
    });
});

需要在jquery ajax验证之前注入客户端js验证

1 个答案: