我自己教Pro * C,这是一个带有游标的程序,通过数据库中的记录,它编译并运行。它只需提示"输入Guest_ID(键入exit to terminate)>>"。之后它会出现错误,因为"分段错误(核心转储)"如果输入整数。如果输入一个字符串,它似乎立即进入外部for循环内的条件
if(nGuest_ID==0)
{
printf("BYE\n");
exit(0);
}
并打印" BYE"然后退出。由于我还熟悉如何通过SQL声明和输入变量,因此我不确定哪些声明对于排除故障可能至关重要,所以我在这里完全保留了代码。
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
exec sql include sqlca;
// OK - Here we GO
void main()
{
// First, create all the variables that we will need to communicate between
// the "C" program and the database
exec sql begin declare section;
//VARCHAR sLastName[51], sFirstName[51], sHotelName[51], sCheckInDate[12], sRoom[11];
VARCHAR sLastName[51], sFirstName[51], sHotelName[51], sTransDate[11];
//int nDays, nGuest_ID, nCount;
int nGuest_ID, nQuantity, nUnitPrice, nCount, nHotelID, nItemID;
//VARCHAR sInCity[11];
VARCHAR sItemName[31], sTaxable[11];
VARCHAR sUserID[21], sPassword[21];
exec sql end declare section;
/////// begin needs work ///////
// Now define the cursor we will use to get all of the charges that the guest incurred at all hotels
exec sql declare dbGuest cursor for
Select G.Guest_ID, G.Last_Name, G.First_Name, C.Item_ID, C.Item_Name, C.Quantity, C.Unit_Price, C.Trans_Date, H.Hotel_Name, H.Hotel_ID, SI.Taxable
From Hotel H, Charge C, Stay S, Guest G, Sales_Item SI Where
C.Stay_ID=S.Stay_ID And H.Hotel_ID=S.Hotel_ID And G.Guest_ID=S.Guest_ID
And SI.Item_ID=C.Item_ID
Group By S.Guest_ID;
//////// end needs work ///////
// Set up the user-id and password to access my database
// Because we are using the local database on this server
// we don't need to use any database location or SID
strcpy(sUserID.arr,"myusername");
strcpy(sPassword.arr,"mypassword");
sUserID.len=strlen(sUserID.arr);
sPassword.len=strlen(sPassword.arr);
exec sql connect :sUserID identified by :sPassword;
// sqlca.sqlcode is a variable that is set based on the last command sent in to the database
// a value anything other than zero for what we just did (connect to the database) indicates
// a error.
if(sqlca.sqlcode !=0)
{
//printf("Sorry, cannot connect to server, pgm aborted %s\n",sqlca.sqlcode); //correction 2/5/14
printf("Sorry, cannot connect to server, pgm aborted %d\n",sqlca.sqlcode); //change to %d
exit(1);
}
//we made it here, so we were able to open the database correctly
exec sql SELECT COUNT(*) INTO :nCount FROM Guest;
printf ("There are %d Guests.\n",nCount);
for(;;){
// Read in through stdio the Guest we want to query, then set it up do we can use it
printf("Enter a Guest_ID(type exit to terminate)>>\n");
scanf("%d",nGuest_ID);
//Guest_ID.len= strlen(Guest_ID.arr);
if(nGuest_ID==0)
{
printf("BYE\n");
exit(0);
}
printf("%s %s %s %s %d\n","Charge Summary for:", sFirstName.arr, sLastName.arr, " Guest_ID:", nGuest_ID);
//printf("I do not work yet (type exit to terminate)>>\n");
// Open our cursor and begin reading records
exec sql open dbGuest;
for(;;)
{
//exec sql fetch dbGuest into :nGuest_ID, :sLastName, :sFirstName, :sHotelName, :sCheckInDate, :nDays, :sRoom;
exec sql fetch dbGuest into :nGuest_ID, :sLastName, :sFirstName, :nItemID, :sItemName, :nQuantity, :nUnitPrice, :sTransDate, :sHotelName, :nHotelID;
if(sqlca.sqlcode !=0) // If anything went wrong or we read past eof, stop the loop
{
break;
}
// Do the crazy stuff to end the C-Strings
sLastName.arr[sLastName.len] = 0;
sFirstName.arr[sFirstName.len] = 0;
sItemName.arr[sItemName.len] = 0;
sTransDate.arr[sTransDate.len] = 0;
sHotelName.arr[sHotelName.len] = 0;
// Print out the information for this guest
printf("%s %d %s %s \n", "Sales_Item: ", nItemID, " - ", sItemName.arr);
}
// close the cursor and end the program
exec sql close dbGuest ;
}
exit(0);
}
我确定我犯了一些简单的错误,但我没有找到任何对搜索有帮助的内容。我在服务器上运行它,并且我没有得到任何调试(这是我迄今为止无法解决的唯一主要错误),所以你拥有的是是)我有的。通常,C程序将在调试器中运行,但这是Pro C,我在整个Oracle Pro C调试事件中丢失了(因为它在远程数据库上运行) 。由于这种错误,我通常怀疑没有正确分配内存,但我在这里看不到类似内容。
通过这些但没有帮助:
Segmentation fault (core dumped) runtime error in C
Not so Useful Error -- Segmentation Fault (Core Dump) in Homework Assignment
答案 0 :(得分:4)
由于nGuest_ID
是一个int,因此在调用scanf()
时,您需要提供nGuest_ID
的地址:
scanf("%d",&nGuest_ID);
这可能是您遇到的核心转储的原因,但是,OracleUser提出了一些很好的建议。
希望有所帮助。