我一直在进行一些mocha / chai测试,除了在每个'it'测试中放置一个循环并迭代一个测试之外,我还没有找到一种在许多不同可能性上运行测试的好方法还有一个时间。问题是,如果我有数十或数百个测试,我不想一遍又一遍地写相同的for循环。
有更优雅的方式吗?特别是一个用不同的测试参数一次遍历所有测试的那个?
describe('As a dealer, I determine how many cards have been dealt from the deck based on', function(){
console.log(this);
beforeEach(function(){
var deck = new Deck();
var myDeck = deck.getCards();
});
it('the number of cards are left in the deck', function(){
for(var i = 1; i<=52; i++){
myDeck.dealCard();
expect(myDeck.countDeck()).to.equal(52-i);
}
});
it('the number of cards dealt from the deck', function(){
expect(myDeck.countDealt()).to.equal(i);
});
it('the sum of the cards dealt and the cards left in the deck', function(){
expect(myDeck.countDeck() + myDeck.countDealt()).to.equal(52)
});
});
答案 0 :(得分:11)
我在Loop Mocha tests?实现了neezer的解决方案,它涉及将整个测试放入一个闭包并用循环执行它。
请注意,循环在函数中与beforeEach()混淆,因为它每次测试执行52次。如果这些元素是动态的,并且每个循环不会执行多次,那么在beforeEach()函数中放置元素不是一个好主意。
代码看起来像这样,似乎有效。
var myDeck = new Deck(Card);
function _Fn(val){
describe('As a dealer, I determine how many cards have been dealt from the deck based on', function(){
myDeck.dealCard();
var cardCount = 0;
var dealtCount = 0;
cardCount = myDeck.countDeck();
dealtCount = myDeck.countDealt();
it('the number of cards are left in the deck', function(){
expect(cardCount).to.equal(52-val);
});
it('the number of cards dealt from the deck', function(){
expect(dealtCount).to.equal(val);
});
it('the sum of the cards dealt and the cards left in the deck', function(){
expect(cardCount + dealtCount).to.equal(52);
});
});
}
for(var i = 1; i<=52; i++){
_Fn(i);
}