Question

这可能是一个愚蠢的问题，但我现在已经有了脑力......

HTML

<b>Comment</b><br>
<select name="text" id="text">
    <option value="">Select a option</option>
    <option value="option1">Option 1</option>
    <option value="option2">Option 2</option>
    <option value="other">Other</option>
</select>

<div class="other box">
    <b>Comment 2</b><br>
    <input type="text" name="own_text">
</div>

如果有人从选择中选择“other”值，我也想确保文本框（own_text）不是NULL，而不是PHP。

试过

if($_POST['text'] == "other" && $_POST['own_text'] != "") {
    echo 'Go on';
} else {
    echo 'You chose other but has not typed anything';
}

使用此代码，我收到了错误消息（您选择了其他但未输入任何内容），即使我选择了“option1”或“option2”，为什么？如果我选择“option1”或“option2”，它会告诉我另一条消息（继续）。

提前致谢！：）

解决方案（感谢Olvathar）

if($_POST['text'] != "other" || $_POST['own_text'] != "") {
    echo 'Go on';
} else {
        echo 'You chose other but has not typed anything';
}

Answer 1

试试这个

if($_POST['text'] == "other" && $_POST['own_text'] != "") {
    echo 'Go on';
} else if($_POST['text'] == "other" && $_POST['own_text'] == "") {{
    echo 'You chose other but has not typed anything';
}else if($_POST['text'] != "other")
{
  // do other things
}

因为如果你只是提到其他它也会有条件，其中$ _POST ['text']未被选为其他

Answer 2

试试这个，

if($_POST['text'] == "other"){
    if($_POST['own_text'] != "") {
        echo 'Go on';
    } else {
        echo 'You chose other but has not typed anything';
    }
}
else{
    if($_POST['text']!=''){
        echo 'Go on';
    }
    else{
        echo 'You must select an option !';
    }        
}

Answer 3

您正在强制选择“其他”继续，请尝试此

if($_POST['text'] != "other" || $_POST['own_text'] != "") {
    echo 'Go on';
 } else {
     echo 'You chose other but has not typed anything';
 }

Answer 4

试试这个：

if(  ($_POST['text'] == "other" || empty($_POST['text'])) && $_POST['own_text'] != "") {
    echo 'Go on';
} else if ($_POST['text'] != "other") {
    echo 'You chose other but has not typed anything';
}

Answer 5

if($_POST['text'] == "other" && $_POST['own_text'] == "") {
   echo 'You chose other but has not typed anything';
} else if($_POST['text'] == "other" && $_POST['own_text'] != "") {
    echo 'You chose other and typed something'; 
} else {
    echo 'go on';
}

PHP：检查选择值和文本框！= NULL

5 个答案: