Question

每当调用新的Socket（“server ip”，portNum）时，我想返回一个已定义的Socket实例，我的代码看起来像这样（我正在使用easymock）

public static  Socket  mockSocket ;
public static  Object []arguments = {"Test Client",8443};
...........................................
..............................................

mockSocket = new Socket("20.206.214.76", 8080);

PowerMock.createMock(Socket.class, arguments);      

expectNew(Socket.class,arguments).andReturn(mockSocket);

它给我编译错误 - ＆gt;

PowerMock.createMock(Socket.class, arguments);

错误是：

"The type org.easymock.ConstructorArgs cannot be resolved. It is indirectly referenced from required .class files"

有人可以帮忙吗？

Answer 1

您的类路径中没有必要的EasyMock jar。编译器正在寻找org.easymock.ConstructorArgs类，但找不到它。

然而，一旦你在类路径中获得了正确的jar，你就需要对Java和嘲笑有所了解。

 // here you create a *real* Socket and assign it to 'mockSocket'
 mockSocket = new Socket("20.206.214.76", 8080);

 // here you create a mock Socket, but don't assign it to anything
 // 'arguments' probably doesn't do what you expect.
 PowerMock.createMock(Socket.class, arguments); 

 // here you tell your test case to intercept calls to `new Socket()` and
 // return mockSocket (which, as we see above) is a real socket.
 expectNew(Socket.class,arguments).andReturn(mockSocket);

您实际需要做的是不创建一个真正的套接字。将您创建的模拟套接字分配给mockSocket，并在expectNew中使用它。您的测试类需要使用@PrepareForTest进行注释，否则expectNew()将无效。

 @RunWith(PowerMockRunner.class)
 @PrepareForTest( MyClass.class )
 public class MyClassTest {
     // ... 
     @Test
     public void testSocket() {
         // create mock object
         Socket mockSocket = PowerMock.createMock(Socket.class);
         // tell test runner to intercept 'new Socket()'
         expectNew(Socket.class,arguments).andReturn(mockSocket); 

         MyClass objectUnderTest = new MyClass();
         // do things to objectUnderTest
         // because of @PrepareForTest and expectNew(), when MyClass
         //    hits 'new Socket(...)' the mock will be returned instead.
         // assert things about objectUnderTest
     }
 }

模拟不适用于Socket类

1 个答案: