仅向单个用户发送消息而不向多个用户发送消息

Question

public class XMPPChatDemoActivity extends Activity {

    public static final String HOST = "talk.google.com";
    public static final int PORT = 5222;
    public static final String SERVICE = "gmail.com";
    public static final String USERNAME = "XXXXXX";
    public static final String PASSWORD = "XXXXXX";

    private XMPPConnection connection;
    private ArrayList<String> messages = new ArrayList<String>();
    private Handler mHandler = new Handler();

    private EditText recipient;
    private EditText textMessage;
    private ListView listview;

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        recipient = (EditText) this.findViewById(R.id.toET);
        textMessage = (EditText) this.findViewById(R.id.chatET);
        listview = (ListView) this.findViewById(R.id.listMessages);
        connect();
        Button send = (Button) this.findViewById(R.id.sendBtn);
        send.setOnClickListener(new View.OnClickListener() {
            public void onClick(View view) {
                String to = recipient.getText().toString();
                String text = textMessage.getText().toString();
                Message msg = new Message(to, Message.Type.chat);
                msg.setBody(text);              
                if (connection != null) {
                    connection.sendPacket(msg);
                    messages.add(text);
                    setListAdapter();
                }
            }
        });
    }

    public void setConnection(XMPPConnection connection) {
        this.connection = connection;
        if (connection != null) {
            // Add a packet listener to get messages sent to us
            PacketFilter filter = new MessageTypeFilter(Message.Type.chat);
            connection.addPacketListener(new PacketListener() {
                @Override
                public void processPacket(Packet packet) {
                    Message message = (Message) packet;
                    if (message.getBody() != null) {
                        String fromName = StringUtils.parseBareAddress(message
                                .getFrom());
                        //  messages.add(fromName + ":");
                        messages.add(message.getBody());
                        // Add the incoming message to the list view
                        mHandler.post(new Runnable() {
                            public void run() {
                                setListAdapter();
                            }
                        });
                    }
                }
            }, filter);
        }
    }

    private void setListAdapter() {
        ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,
                R.layout.list_item, messages);
        listview.setAdapter(adapter);
    }

    @Override
    protected void onDestroy() {
        super.onDestroy();
        try {
            if (connection != null)
                connection.disconnect();
        } catch (Exception e) {

        }
    }

    public void connect() {
        final ProgressDialog dialog = ProgressDialog.show(this,
                "Connecting...", "Please wait...", false);
        Thread t = new Thread(new Runnable() {
            @Override
            public void run() {
                // Create a connection
                ConnectionConfiguration connConfig = new ConnectionConfiguration(
                        HOST, PORT, SERVICE);
                XMPPConnection connection = new XMPPConnection(connConfig);

                try {
                    connection.connect();
                    Log.i("XMPPChatDemoActivity",
                            "Connected to " + connection.getHost());
                } catch (XMPPException ex) {
                    Log.e("XMPPChatDemoActivity", "Failed to connect to "
                            + connection.getHost());
                    Log.e("XMPPChatDemoActivity", ex.toString());
                    setConnection(null);
                }
                try {
                    // SASLAuthentication.supportSASLMechanism("PLAIN", 0);
                    connection.login(USERNAME, PASSWORD);
                    Log.i("XMPPChatDemoActivity",
                            "Logged in as " + connection.getUser());

                    // Set the status to available
                    Presence presence = new Presence(Presence.Type.available);
                    connection.sendPacket(presence);
                    setConnection(connection);

                    }
                } catch (XMPPException ex) {
                    Log.e("XMPPChatDemoActivity", "Failed to log in as "
                            + USERNAME);
                    Log.e("XMPPChatDemoActivity", ex.toString());
                    setConnection(null);
                }

                dialog.dismiss();
            }
        });
        t.start();
        dialog.show();
    }
}

我正在创建一个多人聊天应用程序。我正在使用带有asmack的XMPP，所以为了实现我使用了XMPPDemo代码，但问题是我只能向单个用户发送消息。但是可以接收来自多个用户的消息。我不知道为什么会这样。请提出解决方案。

Answer 1

你想要什么。？如果你想发送多个用户信息，你必须使用MUC创建房间，然后发送如下信息。

 Message msg = new Message(roomjid, Message.Type.groupchat);