Question

我在Jquery中总结和分组我的对象时遇到了问题，因为我希望按国家/地区进行分组，然后根据子期间4,5和6对col1中的值进行总计。 col1，col2，col3是动态的，但使用它就是一个例子。

我需要的是获取存储在国家/地区变量中的国家/地区总数，存储在columns变量中的每个子期间的总计，以及存储在averages变量中的总计数。

这是我在jsfiddle中的代码：

我的对象：

var g_jsonData =

[
{
    "Country": "Spain",
    "Year": "2000",
    "Subperiod": "4",
    "col1": "75",
    "col2": "500",
    "col3": "200"
},
{
    "Country": "Spain",
    "Year": "2001",
    "Subperiod": "4",
    "col1": "50",
    "col2": "500",
    "col3": "300"
},
{
    "Country": "Spain",
    "Year": "2002",
    "Subperiod": "4",      
    "col1": "50",
    "col2": "200",
    "col3": "300"
},
{
    "Country": "Spain",
    "Year": "2003",
    "Subperiod": "4",      
    "col1": "",
    "col2": "200",
    "col3": "300"
},
{
    "Country": "Spain",
    "Year": "2005",
    "Subperiod": "5",
    "col1": "125",
    "col2": "500",
    "col3": "300"
},
{
    "Country": "Spain",
    "Year": "2012",
    "Subperiod": "6",
    "col1": "100.75",
    "col2": "500",
    "col3": "200"
},
{
    "Country": "Spain",
    "Year": "2013",
    "Subperiod": "6",
    "col1": "200",
    "col2": "500",
    "col3": "300"
},
{
    "Country": "France",
    "Year": "2000",
    "Subperiod": "4",    
    "col1": "100",
    "col2": "100",
    "col3": "300"
},
{
    "Country": "France",
    "Year": "2001",
    "Subperiod": "4",      
    "col1": "100",
    "col2": "100",
    "col3": "300"
},
{
    "Country": "France",
    "Year": "2002",
    "Subperiod": "4",      
    "col1": "100",
    "col2": "200",
    "col3": "300"
},
{
    "Country": "France",
    "Year": "2005",
    "Subperiod": "5",      
    "col1": "100",
    "col2": "200",
    "col3": "300"
},
{
    "Country": "France",
    "Year": "2012",
    "Subperiod": "6",      
    "col1": "100",
    "col2": "100",
    "col3": "300"
},
{
    "Country": "France",
    "Year": "2013",
    "Subperiod": "6",      
    "col1": "100",
    "col2": "100",
    "col3": "300"
}];

以下是我想得到的最终结果，这是基于每个国家/地区的每个子时段的总结col1。

countries =    
{
   "Spain":{
      "4":175,
      "5":125,
      "6":300.75
  },    
   "France":{
      "4":300,
      "5":100,
      "6":200,
  }
}

子期间4,5,6的总计应显示为：

columns = 
{
    "4":475,
    "5":225,
    "6":500.75
}

我还想获得每个国家的总计数，每个子期间：

averages = 
{
   "Spain":{
      "4":3,
      "5":1,
      "6":2
  },    
   "France":{
      "4":3,
      "5":1,
      "6":2
  }
}

我想尽可能地坚持我的代码。谢谢，谢谢你的帮助。

Answer 1

这应该可以解决问题：

g_jsonData.reduce(function(out, curr){
    // Make sure the current country exists on the output object.
    // Then add the current object's col1 to the current country's subperiod,
    //   checking to see if the current subperiod exists. Also, cast the `col1` to int `(+curr.col1)`
    out.countries[curr.Country] = out.countries[curr.Country] || {};
    out.countries[curr.Country][curr.Subperiod] = (out.countries[curr.Country][curr.Subperiod] || 0) + (+curr.col1);

    // And add it to the total, too.
    out.columns[curr.Subperiod] = (out.columns[curr.Subperiod] || 0) + (+curr.col1);

    // Count occurences
    out.count[curr.Country] = out.count[curr.Country] || {};
    out.count[curr.Country][curr.Subperiod] = (out.count[curr.Country][curr.Subperiod] || 0) + 1;
    return out;
},
{'columns':{},'countries':{},'count':{}}); // second parameter to `reduce` is a default object, in this case: `{'columns':{},'countries':{},'count':{}}}`

返回：

{
    "columns": {
        "4": 475,
        "5": 225,
        "6": 500.75
    },
    "countries": {
        "Spain": {
            "4": 175,
            "5": 125,
            "6": 300.75
        },
        "France": {
            "4": 300,
            "5": 100,
            "6": 200
        }
    },
    "count": {
        "Spain": {
            "4": 3,
            "5": 1,
            "6": 2
        },
        "France": {
            "4": 3,
            "5": 1,
            "6": 2
        }
    }
}

请注意，这不会更改 g_jsonData，它只返回新对象。
要使用新对象，您必须将其分配给变量，当然：

var output = g_jsonData.reduce(func....);

您可以使代码更短（/更容易看），如下所示：

g_jsonData.reduce(function(out, curr){
    var c = curr.Country,
        s = curr.Subperiod,
        v = +curr.col1; //value cast to int already
    out.countries[c]    =  out.countries[c]    || {};
    out.countries[c][s] = (out.countries[c][s] || 0 ) + v;
    out.count[c]        =  out.count[c]        || {};
    out.count[c][s]     = (out.count[c][s]     || 0 ) + 1;
    out.columns[s]      = (out.columns[s]      || 0 ) + v;
    return out;
},
{'columns':{},'countries':{},'count':{}});

现在，col1变量名称相对容易替换：

v = +curr.col1;

使用：

v = +curr['col1'];

或者：

v = +curr[someVariable];

在Jquery中汇总和分组JSON对象

1 个答案: