Question

以下是发生的事情：我给变量“pay”一个值。例如16。我使用printf打印付款，然后我回来了16。然后我再次打印，然后得到0.如果我第三次打印它，我再次打16。

此外，无论我做什么，我似乎总是为员工类型获得0。

感谢任何帮助。谢谢！

#include<stdlib.h>
#include<stdio.h>

int main(void)
{

float pay;

int employees;
int type;
int hours;
int items;
int i;
int j;

printf("How many employees? ");
scanf("%d", &employees);

float array[employees][2];

for(i = 0; i < employees; i++)
{
    printf("\nWhat type of employee is employee #%d?", i + 1);
    printf("\nEnter \"1\" for Manager.\nEnter \"2\" for Hourly Worker.\nEnter \"3\" for Commission Worker.\nEnter \"4\" for Pieceworker.");
    scanf("%d", &type);

    switch (type) 
    {
        case 1:
            array[i][0] = 1;
            printf("\nWhat is the weekly pay for employee #%d (manager)?", i + 1);
            scanf("%f", &pay);

            array[i][1] = pay;
            printf("\nEmployee #%d earned $%.2f this week.", i + 1, array[i][1]);

            break;

        case 2:
            array[i][0] = 2;
            printf("\nWhat is the hourly pay for employee #%d (Hourly Worker)?", i + 1);
            scanf("%f", &pay);

            printf("\nHow many hours did employee #%d work this week?", i + 1);
            scanf("%d", &hours);

            if (hours > 40)
            {
                pay = ((hours - 40) * pay * 1.5) + (hours * pay);
            }
            else
                pay *= hours;

            array[i][1] = pay;
            printf("\nEmployee #%d earned $%.2f this week.", i + 1, array[i][1]);

            break;

        case 3:
            array[i][0] = 3;
            printf("\nWhat were the gross sales for employee #%d (Commission Worker)?", i + 1);
            scanf("%f", &pay);

            pay = (pay *.057) + 250;

            array[i][1] = pay;
            printf("\nEmployee #%d earned $%.2f this week.", i + 1, array[i][1]);

            break;

        case 4:
            array[i][0] = 4;
            printf("\nHow many items did employee #%d (Pieceworker) produce this week?", i + 1);
            scanf("%d", &items);

            printf("\nHow much does employee #%d get paid for every item they produce?", i + 1);
            scanf("%f", &pay);

            pay *= items;

            array[i][1] = pay;
            printf("\nEmployee #%d earned $%.2f this week.", i + 1, array[i][1]);

            break;
    }
    array[i][0] = type;
    printf("\n\nEmployee type: %d", array[i][0]);
    printf("\nEmployee #%d earned $%.2f this week.", i + 1, array[i][1]);


}

printf("\n\nEmployee # | Employee Type | Weekly Pay");

for(j = 0; j < employees; j++)
{
    printf("\n%10d | %13d | $%.2f", j + 1, array[j][0], array[j][1]);
}

}

编辑：现在我可以获得付费打印的价值。但是，当我尝试打印员工类型时，我仍然得到0。

此外，打印图表的最终循环仍在两个值上返回0。有任何想法吗？（以上代码更新）

Answer 1

float array[employees - 1][2];
:
for(i = 0; i < employees; i++)
    :
    blah blah blah ... array[i][2] ...

您正在数组范围之外访问。

当您定义array[42]之类的内容时，数组元素会按值0到41进行索引。 C使用从零开始的索引。

你似乎超越了两个维度的界限，首先使用employees - 1创建第一个维度，然后使用2作为第二个维度的索引，尽管事实上你应该只是使用0和1。

在尝试解决任何其他问题之前，我先解决这个未定义的行为。

Answer 2

似乎是数组索引是错误的，它从0开始，但你已经使用了1和2

C变量在打印时失去价值

2 个答案: