我在我的Spring Web MVC项目中使用Java配置实现Spring Security,并且由于某种原因,@Autowired
注释不是在我的安全配置类中注入字段。我在SO上发现了this非常相似的问题,但我的设置很多更简单,并且在我的情况下,接受的答案根本不适用。
作为参考,我遵循了Spring自己的安全文档(here)的前三章,并且内存中的身份验证工作非常快。然后,我想切换到JDBC身份验证,并使用DataSource
注释注入@Autowired
(如this example所示)。但是,我收到了这个错误:
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'securityConfig': Injection of autowired dependencies failed; nested exception is org.springframework.beans.factory.BeanCreationException: Could not autowire field: private javax.sql.DataSource com.tyedart.web.config.security.SecurityConfig.dataSource; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No qualifying bean of type [javax.sql.DataSource] found for dependency: expected at least 1 bean which qualifies as autowire candidate for this dependency. Dependency annotations: {@org.springframework.beans.factory.annotation.Autowired(required=true)}
这是我的安全配置类。正如您所看到的,我通过明确查找我的数据源解决了这个问题:
@Configuration
@EnableWebMvcSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
// @Autowired
// private DataSource dataSource;
// @Autowired
// public PasswordEncoder passwordEncoder;
@Autowired
public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
InitialContext ctx = new InitialContext();
DataSource dataSource = (DataSource) ctx.lookup("java:/comp/env/jdbc/TyedArtDB");
PasswordEncoder passwordEncoder = new BCryptPasswordEncoder();
auth
.jdbcAuthentication()
.dataSource(dataSource)
.passwordEncoder(passwordEncoder);
}
@Override
public void configure(HttpSecurity http) throws Exception {
http
.authorizeRequests()
.antMatchers("/manage/**").hasRole("ADMIN")
.and()
.formLogin();
}
}
这是我非常简单的root-context.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:jee="http://www.springframework.org/schema/jee"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd">
<!-- Root Context: defines shared resources visible to all other web components -->
<jee:jndi-lookup id="dataSource" jndi-name="jdbc/TyedArtDB"/>
<bean id="passwordEncoder" class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder"/>
</beans>
我做错了什么?
答案 0 :(得分:1)
在root-context.xml中添加<context:component-scan base-package="your.package.where.your.bean.is"/>
您可以取消注释@Autowired in字段声明并将其从约束器中删除。您可以找到更多信息here
如果您@Autowired
是一个bean,请不要忘记使用new
删除初始化。
答案 1 :(得分:0)
我不是百分百肯定,但看起来问题是你正在尝试Autowire DataSource,它实际上并没有被定义为Spring bean:
<jee:jndi-lookup id="dataSource" jndi-name="jdbc/TyedArtDB"/>
创建一个可以在XML中引用的对象,但是不认为它实际上创建了一个bean? (可能是错的,春天的JNDI查找并没有那么多。)
是否可以切换到纯java配置并删除XML引用?
@Bean
public DataSource dataSource() throws Exception {
Context ctx = new InitialContext();
return (DataSource) ctx.lookup("jdbc/TyedArtDB");
}
(取自这个答案:https://stackoverflow.com/a/15440797/258813)
你可以像这样移动密码编码器:
@Bean public BCryptPasswordEncoder bCryptPasswordEncoder(){
return new BCryptPasswordEncoder();
}
取自:http://automateddeveloper.blogspot.co.uk/2014/02/spring-4-xml-to-annotation-configuration.html
答案 2 :(得分:0)
这是我用来自动装配BCryptPasswordEncoder的一个例子:
<强> UserServiceImpl.java 强>
@Service("userService")
public class UserServiceImpl implements UserService {
@Autowired
BCryptPasswordEncoder bCryptPasswordEncoder;
@Override
public User findUserByEmail(String email) {
return null;
}
}
<强> WebMvcConfig.java 强>
@Configuration
public class WebMvcConfig extends WebMvcConfigurerAdapter {
@Bean
public BCryptPasswordEncoder passwordEncoder(){
BCryptPasswordEncoder bCryptPasswordEncoder = new BCryptPasswordEncoder();
return bCryptPasswordEncoder;
}
}
如果您注意到,WebMvcConfig.java在passwordEncoder()方法之前就有@Bean注释。它表明一个方法生成一个由Spring容器管理的bean。