出于某种原因,我得到的数学价值不同于我应有的数学价值。我在这里做错了什么?
代码:
overtimeHours = hoursWorked - 40;
regularPay = hourlyWage * hoursWorked - overtimeHours;
overtimePay = 1.5 * hourlyWage * overtimeHours;
totalPay = hourlyWage * hoursWorked + overtimePay;
输出:
Please enter employee's name: John
Please enter The Dragon's hourly wage: 22.50
Please enter how many hours The Dragon worked: 48.5
John's Wages
Regular Pay: $ 1082.75
Overtime Pay: $ 286.88
Total Pay: $ 1378.13
答案 0 :(得分:9)
操作顺序,就像你在基础数学中学到的一样。你正在计算
(hourlyWage * hoursWorked) - overtimeHours
相反,你想要
hourlyWage * (hoursWorked - overtimeHours)
此外,您不应该在total
中重新计算;相反,只需添加常规和加班。
最后,正如@CodeMonkey所说,你无条件地假设这个人正在加班。以下是我的建议:
if(hoursWorked > 40) {
regularHours = 40;
overtimeHours = regularHours - 40;
} else {
regularHours = hoursWorked;
overtimeHours = 0;
}