Question

我看过所有关于这个主题的问题，但无法理解它。它在三星Galaxy S4上进行了测试。这来自我的activity_main.xml。

<LinearLayout
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:id="@+id/llListe"
    android:orientation="vertical"
    >
    <ListView
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:id="@+id/lstListe"
        android:layout_gravity="center"
        android:background="#bcffb9" />
</LinearLayout>

这是MainActivity.java。我已经测试了来自speechRecognizer的结果并返回了说出的单词。问题是将此字符串添加到ListView。我已经放弃了，所以请原谅。我做错了什么？

public class MainActivity extends Activity implements View.OnClickListener {

protected static final int REQUEST_OK = 1;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    findViewById(R.id.btnSpeek).setOnClickListener(this);
}

@Override
public void onClick(View v) {
    Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
    intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL,"en-US");
    try {
        startActivityForResult(intent,REQUEST_OK);
    } catch (Exception e) {
        Toast.makeText(this, "Unable to initialize speech engine.", Toast.LENGTH_LONG).show();
    }
}

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    ListView lv;
    ArrayList<String> inputString =  new ArrayList<String>();
    ArrayAdapter<String> adapter;
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode==REQUEST_OK && resultCode==RESULT_OK) {
        inputString = (data.getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS));
        //Toast.makeText(this,"You said "+inputString.get(0), Toast.LENGTH_SHORT).show();
        lv = (ListView) findViewById(R.id.lstListe);
        adapter = new ArrayAdapter(this,R.id.lstListe,inputString);
        lv.setAdapter(adapter);

    }
}

}

Answer 1

我认为您应该将此行super.onActivityResult(requestCode, resultCode, data);放在onActivityResult方法的else条件中，以便在请求代码为REQUEST_OK时确保您的代码已执行。

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    ListView lv;
    ArrayList<String> inputString =  new ArrayList<String>();
    ArrayAdapter<String> adapter;

    if (requestCode==REQUEST_OK && resultCode==RESULT_OK) {
        inputString = (data.getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS));
        //Toast.makeText(this,"You said "+inputString.get(0), Toast.LENGTH_SHORT).show();
        lv = (ListView) findViewById(R.id.lstListe);
        adapter = new ArrayAdapter(this,R.id.lstListe,inputString);
        lv.setAdapter(adapter);
    } 
    else {
        super.onActivityResult(requestCode, resultCode, data);
    }
}

Listview和适配器适用于假人

1 个答案: