问题从oracle存储过程中的日期字段检索时间

时间:2010-02-02 17:22:03

标签: oracle stored-procedures

我在从SP中的日期字段中检索时间时遇到问题。如果我运行查询:

select TO_CHAR(HOR_HST_ATN,'YYYY/MM/DD HH24:MI:SS') AS HOR_HST_ATN FROM AAM0_DT_RSTCN ;

它返回日期和时间。

但在SP中,代码:

SELECT   FEC_DSD_ATN, FEC_HST_ATN, NOM_SEM_DSD_ATN, NOM_SEM_HST_ATN, 
    TO_DATE(HOR_DSD_ATN ,'DD/MM/YYYY HH24:MI:SS') as  HOR_DSD_ATN,
    TO_DATE(HOR_HST_ATN,'DD/MM/YYYY HH24:MI:SS') as HOR_HST_ATN

只返回日期,但时间是00:00

如果我在SP中使用TO_CHAR尝试选择:

SELECT   FEC_DSD_ATN, FEC_HST_ATN, NOM_SEM_DSD_ATN, NOM_SEM_HST_ATN,
 TO_CHAR(HOR_DSD_ATN ,'YYYY/MM/DD HH24:MI:SS') as  HOR_DSD_ATN,
 TO_CHAR(HOR_HST_ATN,'YYYY/MM/DD HH24:MI:SS') as HOR_HST_ATN

我收到错误: SQLCODE:-6502 SQLERRM:ORA-06502:PL / SQL:错误...

任何线索?顺便说一下,我必须使用SP来检索这个值。

更新:列是类型日期。这是完整的SP:

FUNCTION FN_AAM_EV_RSTCN ( 

I_NUM_CONTRATO            IN  AAM0_DT_RSTCN.NUM_CONTRATO%TYPE,
I_COD_PFL                  IN  AAM0_DT_RSTCN.COD_PFL%TYPE, 
I_COD_APL_PFM              IN  AAM0_DT_RSTCN.COD_APL_PFM%TYPE, 
I_COD_PTO                  IN  AAM0_DT_RSTCN.COD_PTO%TYPE, 
I_COD_FNC                  IN  AAM0_DT_RSTCN.COD_FNC%TYPE
) RETURN BOOLEAN
AS
T_FEC_DSD_ATN                   AAM0_DT_RSTCN.FEC_DSD_ATN%TYPE;
T_HOR_DSD_ATN                   AAM0_DT_RSTCN.HOR_DSD_ATN%TYPE;
T_FEC_HST_ATN                   AAM0_DT_RSTCN.FEC_HST_ATN%TYPE;
T_HOR_HST_ATN                   AAM0_DT_RSTCN.HOR_HST_ATN%TYPE;
T_NOM_SEM_DSD_ATN               AAM0_DT_RSTCN.NOM_SEM_DSD_ATN%TYPE;
T_NOM_SEM_HST_ATN               AAM0_DT_RSTCN.NOM_SEM_HST_ATN%TYPE;

 O_RESULTSET2          REST_REFCUR;

BEGIN
 OPEN O_RESULTSET2 FOR 

   SELECT   FEC_DSD_ATN, FEC_HST_ATN, NOM_SEM_DSD_ATN, NOM_SEM_HST_ATN, 
    TO_CHAR(HOR_DSD_ATN ,'DD/MM/YYYY HH24:MI:SS') as  HOR_DSD_ATN,
    TO_CHAR(HOR_HST_ATN,'DD/MM/YYYY HH24:MI:SS') as HOR_HST_ATN
    FROM    AAM0_DT_RSTCN
    WHERE ROWNUM <=1
    AND   NUM_CONTRATO          = NVL ( I_NUM_CONTRATO, NUM_CONTRATO )
    AND     COD_PFL               = NVL ( I_COD_PFL, COD_PFL )
    AND     COD_APL_PFM           = NVL ( I_COD_APL_PFM, COD_APL_PFM )
    AND     COD_PTO               = NVL ( I_COD_PTO, COD_PTO )
    AND     COD_FNC               = NVL ( I_COD_FNC, COD_FNC )    
    AND     FLG_RCS               = 'D'
    AND     COD_TPO_CDC           = 'PC'
    ;

   FETCH O_RESULTSET2 INTO T_FEC_DSD_ATN, T_FEC_HST_ATN, T_NOM_SEM_DSD_ATN, T_NOM_SEM_HST_ATN, T_HOR_DSD_ATN, T_HOR_HST_ATN ;

  IF (O_RESULTSET2%NOTFOUND) THEN
    RETURN TRUE;
  ELSE
   dbms_output.put_line('EVALUO RESTRICCIONES: T_FEC_DSD_ATN '  || T_FEC_DSD_ATN || ' T_FEC_HST_ATN : ' || T_FEC_HST_ATN || ' T_NOM_SEM_DSD_ATN: ' ||
                 T_NOM_SEM_DSD_ATN || ' T_NOM_SEM_HST_ATN: '  || T_NOM_SEM_HST_ATN || ' T_HOR_DSD_ATN: ' || TO_CHAR(T_HOR_DSD_ATN ,'DD/MM/YYYY HH24:MI:SS')  || 
                ' T_HOR_HST_ATN: ' || TO_CHAR(T_HOR_HST_ATN ,'DD/MM/YYYY HH24:MI:SS') );

     IF (NOT((T_FEC_DSD_ATN IS NULL) and (T_FEC_HST_ATN IS NULL)) ) THEN

       IF ( NOT ((T_FEC_DSD_ATN  <= SYSDATE) AND (T_FEC_HST_ATN >= SYSDATE ))) THEN
                RETURN FALSE;
        END IF ;

    END IF ;

  RETURN TRUE;

  END IF ;

EXCEPTION

  WHEN NO_DATA_FOUND THEN
    RETURN TRUE; 

  WHEN OTHERS THEN


    IF O_RESULTSET2%ISOPEN THEN

      CLOSE O_RESULTSET2;

    END IF;


    DBMS_OUTPUT.PUT_LINE('ERROR en FN_AAM_EV_RSTCN : '); 
    DBMS_OUTPUT.PUT_LINE('  SQLCODE: ' || SQLCODE );
    DBMS_OUTPUT.PUT_LINE('  SQLERRM: ' || SQLERRM );

    ROLLBACK;

 END FN_AAM_EV_RSTCN;

4 个答案:

答案 0 :(得分:3)

您的问题在于以下代码:

...
T_HOR_DSD_ATN                   AAM0_DT_RSTCN.HOR_DSD_ATN%TYPE;
T_HOR_HST_ATN                   AAM0_DT_RSTCN.HOR_HST_ATN%TYPE;
...
SELECT   FEC_DSD_ATN, FEC_HST_ATN, NOM_SEM_DSD_ATN, NOM_SEM_HST_ATN, 
TO_CHAR(HOR_DSD_ATN ,'DD/MM/YYYY HH24:MI:SS') as  HOR_DSD_ATN,
TO_CHAR(HOR_HST_ATN,'DD/MM/YYYY HH24:MI:SS') as HOR_HST_ATN
FROM    AAM0_DT_RSTCN
...
FETCH O_RESULTSET2 INTO T_FEC_DSD_ATN, T_FEC_HST_ATN, T_NOM_SEM_DSD_ATN,
T_NOM_SEM_HST_ATN, T_HOR_DSD_ATN, T_HOR_HST_ATN ;

由于HOR_DSD_ATNHOR_HST_ATN列具有DATE数据类型,因此您的本地变量(T_HOR_DSD_ATNT_HOR_HST_ATN)也是DATE。但是,在SELECT中,您将这些日期转换为具有TO_CHAR函数的字符串。因此,你的fetch实际上是这样做的(我在这里编写了一些日期):

T_HOR_DSD_ATN := '03/02/2010 09:33:30';
T_HOR_HST_ATN := '01/01/2010 12:30:00';

由于您要将字符串分配给日期变量,因此Oracle必须执行隐式TO_DATE - 因此它使用会话的NLS_DATE_FORMAT来转换它们,这可能只是获取日期部分(例如DD/MM/YYYY)并且丢失了时间价值。

要修复它,只需从SELECT语句中删除TO_CHAR() - 这样就可以将日期+时间值未修改为局部变量。

答案 1 :(得分:2)

由于TO_DATE函数将VARCHAR作为参数,因此不会在DATE字段上使用此函数。如果要从DATE字段中检索日期和时间,则只需选择不带函数的字段:

SELECT   FEC_DSD_ATN, FEC_HST_ATN, NOM_SEM_DSD_ATN, NOM_SEM_HST_ATN, 
         HOR_DSD_ATN, HOR_HST_ATN
   ...

更新

问题在于您将TO_CHAR(HOR_DSD_ATN, 'DD/MM/YYYY HH24:MI:SS')提取到DATE字段中。隐式转换会截断您的日期。在DATE变量上使用to_char,在CHAR变量上使用to_date

我的建议:

FUNCTION FN_AAM_EV_RSTCN(I_NUM_CONTRATO IN AAM0_DT_RSTCN.NUM_CONTRATO%TYPE,
                         I_COD_PFL      IN AAM0_DT_RSTCN.COD_PFL%TYPE,
                         I_COD_APL_PFM  IN AAM0_DT_RSTCN.COD_APL_PFM%TYPE,
                         I_COD_PTO      IN AAM0_DT_RSTCN.COD_PTO%TYPE,
                         I_COD_FNC      IN AAM0_DT_RSTCN.COD_FNC%TYPE) 
   RETURN BOOLEAN AS
BEGIN
   FOR cc IN (SELECT FEC_DSD_ATN, FEC_HST_ATN, NOM_SEM_DSD_ATN, 
                     NOM_SEM_HST_ATN, HOR_DSD_ATN, HOR_HST_ATN
                FROM AAM0_DT_RSTCN
               WHERE ROWNUM <= 1
                 AND NUM_CONTRATO = NVL(I_NUM_CONTRATO, NUM_CONTRATO)
                 AND COD_PFL = NVL(I_COD_PFL, COD_PFL)
                 AND COD_APL_PFM = NVL(I_COD_APL_PFM, COD_APL_PFM)
                 AND COD_PTO = NVL(I_COD_PTO, COD_PTO)
                 AND COD_FNC = NVL(I_COD_FNC, COD_FNC)
                 AND FLG_RCS = 'D'
                 AND COD_TPO_CDC = 'PC') LOOP
      dbms_output.put_line(' T_HOR_DSD_ATN: ' || 
                           TO_CHAR(cc.HOR_DSD_ATN, 'DD/MM/YYYY HH24:MI:SS') ||
                           ' T_HOR_HST_ATN: ' || 
                           TO_CHAR(cc.HOR_HST_ATN, 'DD/MM/YYYY HH24:MI:SS'));
      -- your logic with return boolean
   END LOOP;
   -- no rows found
   RETURN TRUE;
EXCEPTION
   WHEN OTHERS THEN
      DBMS_OUTPUT.PUT_LINE('ERROR en FN_AAM_EV_RSTCN : ');
      DBMS_OUTPUT.PUT_LINE('  SQLCODE: ' || SQLCODE);
      DBMS_OUTPUT.PUT_LINE('  SQLERRM: ' || SQLERRM);
      RAISE;
END FN_AAM_EV_RSTCN;

答案 2 :(得分:0)

如果HOR_HST_ATN是日期列,则TO_DATE(HOR_HST_ATN,'DD/MM/YYYY HH24:MI:SS')必须是拼写错误。你可能意味着TO_CHAR()。

答案 3 :(得分:0)

如果列由没有时间元素的日期填充,则Oracle将默认时间设置为午夜...

SQL> create table t23 (d date)
  2  /

Table created.

SQL> insert into t23 values (sysdate)
  2  /

1 row created.

SQL> insert into t23 values (to_date('03-FEB-2010', 'DD-MON-YYYY'))
  2  /

1 row created.

SQL> select to_char(d, 'DD/MM/YYYY HH24:MI:SS') as datetime from t23
  2  /

DATETIME
-------------------
02/02/2010 17:59:51
03/02/2010 00:00:00

SQL>