Question

此screenshot是我的结果。

如何获取相同ID的最高记录？（查询结果有3条记录，但我想记录最高记录）

谢谢我的代码İs但我有错误（'CTE'多次指定了'ID'列。）

WITH CTE AS
(
   SELECT RN = ROW_NUMBER() OVER (PARTITION BY dbo.Product.ID ORDER BY dbo.Picture.UpdatedDate ASC), *
   FROM Dbo.Product
   inner JOIN dbo.Product_Picture_Mapping on dbo.Product_Picture_Mapping.ProductID = dbo.Product.ID
   inner join dbo.Picture on dbo.Picture.ID = dbo.Product_Picture_Mapping.PictureID
)
SELECT * FROM CTE WHERE RN = 1
ORDER BY dbo.Picture.UpdatedDate DESC

Answer 1

没有固有的“顶部”或“底部”，因此您需要指定要排序的列。但是，您可以使用ROW_NUMBER为每个ID获取一条记录。

例如（假设UPDATEDDATE为order-column）：

WITH CTE AS
(
   SELECT RN = ROW_NUMBER() OVER (PARTITION BY ID ORDER BY UPDATEDDATE ASC), *
   FROM rbo.Product INNER JOIN ....
)
SELECT * FROM CTE WHERE RN = 1
ORDER BY UPDATEDDATE DESC

（用联接替换....，我不想从你的图像中输入它们）

Answer 2

您可以使用top 1 with ties选项。

select top 1 with ties *
from ...
order by id

Answer 3

;with TempTb as (Select ID, Name,ShortDesc, Count =ROW_NUMBER()
                over(PARTITION By ID Order By ID)
                From YourTable
                )

Select * from TempTb where Count =1

Sql Query选择一个记录

3 个答案: