Question

我使用PHP向另一个Web服务器发出HTTP请求以检索JSON数据，该请求似乎有效，我可以使用var_dump查看数据，但我不确定我是否可以访问数据。

这是我获取数据的代码：

$response = Requests::get($mydetails);

$array1 = json_decode(json_encode($response), true);

我尝试的几乎所有内容（例如echo $ array1-＆gt; operation-＆gt; result-＆gt; status）都给出了相同的错误消息：

PHP Notice:  Trying to get property of non-object

这是var_dump输出的前几行：

 array(9) {
  ["body"]=>
  string(7017) "{"operation":{"result":{"status":"Success","message":"Request details listed successfully"},"details":[{"fields":[{"name":"requesttype","value":"Incident","type":"Pick List","displayvalue":"Request Type","allowedvalues":["Incident","Request for Change","Request For Information","Request for Work"],"mandatory":"false"},{"name":"impact","value":"Affects User","type":"Pick List","displayvalue":"Impact","allowedvalues":["Affects Business","Affects Department","Affects Group","Affects User"],"mandatory":"false"},{"name":"status","value":"Closed","type":"Pick List","displayvalue":"Status","allowedvalues":["Awaiting Customer","Awaiting Third Party","Closed","More Information Required","Open","Resolved"],"mandatory":"false"},{"name":"impactdetails","value":"-","type":"Multi Line","displayvalue":"Impact Details","allowedvalues":[""],"mandatory":"false"},{"name":"mode","value":"Phone Call","type":"Pick List","displayvalue":"Mode","allowedvalues":["Customer Portal","E-Mail","Fax","On-Site Request","Phone Call"],"mandatory":"false"},{"name":"priority","value":"Severity 2","type":"Pick List","displayvalue":"Priority","allowedvalues":["National Level 1","National Level 2","Request for Change","Severity 1","Severity 2","Severity 3","Severity 4"],"mandatory":"false"},{"name":"department","value":"General Practice","type":"Not Editable","displayvalue":"Department","allowedvalues":[""],"mandatory":"true"},{"name":"requesteremail","value":"","type":"Not Editable","displayvalue":"E-mail","allowedvalues":[""],"mandatory":"false"},{"name":"requestercontactnumber","value":"","type":"Not Editable","displayvalue"

Answer 1

解码后的结构是array，因此您应该使用$array1['body']['operation']['result']['status']之类的数组运算符访问它，而不是-> - 这是对象遍历运算符。您也可以将其解码为对象：

$response = Requests::get($mydetails);

$array1 = json_decode(json_encode($response));

但是您的回复似乎已经是array了，所以只需访问它，而无需重新编码，可能吗？

修改在对代码做了一些假设之后，你应该这样做：

$response = Requests::get($mydetails); $array1 = json_decode($response['body'], true); var_dump($array1); // looks ok?

Answer 2

如果对json解码使用true属性，则将json置于关联数组中，因此您需要使用范围访问

$array1['operation']['result']['status'];

已成功获取JSON PHP数据，但我无法访问它

2 个答案: