Question

我有这个查询，显然它有问题吗？我正在尝试与fices加入mems，因此我可以将ficeID以及mems的所有结果（这些查询单独运行）。我做错了什么？

  SELECT * 
    FROM mems 
   WHERE deleted <> -1 
ORDER BY sort_mems 
         LEFT JOIN SELECT ficeID 
                     FROM fices

结果：

 #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LEFT JOIN SELECT ficeID FROM offices LIMIT 0, 30' at line 1

Answer 1

JOIN之后您有ORDER BY个子句。您应该将其放在FROM。
我建议您定义LEFT JOIN

另外，我建议你用括号围绕临时表：

  SELECT m.*, t1.officeID
    FROM members m
         LEFT JOIN offices t1
                   ON m.memberID = t1.memberID
   WHERE m.deleted <> -1 
ORDER BY m.sort_membername;

Answer 2

是的，您的LEFT JOIN位于错误的位置（它应该在您的FROM子句之后，并且您似乎也错过了加入条件（ON部分，这告诉数据库这些表是如何相关的）：

SELECT *
FROM mems m
LEFT JOIN fices f
  ON  m.??? = f.???
WHERE deleted <> -1 
ORDER BY sort_mems

在Database SQL中测试时查询错误

2 个答案: