Question

在表单验证中，当前密码必须与我登录的密码匹配。如果我引入的当前密码与我用于登录的密码匹配，我可以更改它。但它不起作用，我可以在我当前的密码字段中输入任何密码。我的问题是如何在匹配函数中输入我用来登录的密码。（我用来记录的密码存储在会话中）。

function edit_info()

{
    $this->load->helper(array('form', 'url'));
    $this->load->library('session');
    $this->load->library('form_validation');
    $this->form_validation->set_rules('firstname2','FirstName','trim|required');
    $this->form_validation->set_rules('lastname2','LastName','trim|required');
    $this->form_validation->set_rules('current_password','Current Password','trim|required|matches(password)');
    $this->form_validation->set_rules('password3','Password','trim|required|min_length[4]|max_length[32]');

    if($this->form_validation->run() == FALSE)
    {
        $this->edit();  
    }
    else
    {   

        $this->load->model('membership_model');
        if($this->membership_model->edit_member())
        {
            $data['main_content']='edit_successful';
            $this->load->view('includes/template',$data);
        }
        else
        {
            $this->load->view('main_menu'); 
        }
    }
}

Answer 1

您需要对控制器内的函数进行回调。

// call function to check
$this->form_validation->set_rules('current_password','Current Password','trim|required|callback_password_check');

// do your check and return false or true
public function password_check($str){

}

转到：http://ellislab.com/codeigniter%20/user-guide/libraries/form_validation.html#callbacks

匹配函数参数codeigniter

1 个答案: