我想让总交易量超过50000的用户
SELECT sum(tractions.amount) as total , user_id FROM `tractions` where `total` > 50000 group by user_id
我收到此错误
#1054 - Unknown column 'total' in 'where clause'
诅咒表中没有总列,但我应该怎么写这个条件?
答案 0 :(得分:4)
您需要一个聚合总计的having
子句:
SELECT sum(tractions.amount) as total , user_id
FROM `tractions`
group by user_id
HAVING total > 50000;
编辑:
如果我正在编写此查询,它将如下所示:
select t.user_id, sum(t.amount) as total
from tractions t
group by t.user_id
having sum(t.amount) > 50000;
我发现大写的关键词让人分心。我(几乎)总是在一行的开头放置我聚合的字段。我大量使用表别名,它们是表的缩写。我没有转义标识符,因为我从不在标识符中使用保留字或特殊字符。我把表达式放在having
子句中因为。 。 。好吧,我认为曾几何时,并非所有数据库都支持在having
子句中使用列别名。
答案 1 :(得分:0)
试试这个
SELECT sum(tractions.amount) as total , user_id FROM `tractions` where sum(tractions.amount) > 50000 group by user_id
答案 2 :(得分:0)
SELECT sum(tractions.amount) as total , user_id
FROM `tractions`
where sum(tractions.amount) > 50000
group by user_id
答案 3 :(得分:0)
SELECT
sum(tractions.amount) as total, user_id
FROM
`tractions`
group by user_id
having total > 50000;