Question

我要求编写MS-SQL存储过程，要求是表1
它包括分期支付的学生总费用 EX：

SID   SNAME     INST.Date   Amount

123     XYZ     01-01-2013  3500
123     XYZ     01-05-2013  3500
123     XYZ     01-10-2013  3500
123     XYZ     01-04-2014  3500
123     XYZ     01-06-2014  3500

`
表2
它包括付款recd详细信息

SID     SNAME    Paydate    amoount
123     XYZ     01-01-2013  1167
123     XYZ     01-02-2013  1167
123     XYZ     01-03-2013  1167
123     XYZ     01-05-2013  1750
123     XYZ     01-05-2013  1750
123     XYZ     01-10-2013  1167
123     XYZ     01-10-2013  1167

现在的要求是2014年1月，支付了多少分期付款，什么是Recd金额，没有按照jan-14支付的余额分期付款。

预期输出

SID     Sname   Total Inst.Amt as on01.01.2014  Paid.amount     Balance amt     Balance.Installments

123     XYZ     10500                           9335            1165            1

作为参考，我给了一个学生数据。

存储过程应该适用于36000名学生。

Answer 1

这是一个可以满足您想要的问题，期待Balance.Installments我不知道这意味着什么：

SELECT distinct t1.SID
, t1.SNAME
, t1.Total_Inst
, t2.Paid_amount AS 'Paid.Amount'
, t1.Total_Inst - t2.Paid_amount as 'Balance amt'
, CEILING( (t1.Total_Inst - t2.Paid_amount) / t.Amount ) as 'Balance.Installments'
FROM
    table_1 as t
    JOIN
    ( SELECT SID, SNAME, SUM(Amount) as Total_Inst 
      FROM table_1 
      WHERE Date < STR_TO_DATE('01/01/2014', '%m/%d/%Y') group by SID, SNAME
    )
    ON ( t1.SID = t.SID AND t1.SNAME = t.SNAME )
    AS t1
    LEFT JOIN
    ( SELECT SID, SNAME, SUM(Amount) as Paid_amount 
      FROM table_2 
      WHERE Paydate < STR_TO_DATE('01/01/2014', '%m/%d/%Y') group by SID, SNAME
    ) AS t2
    ON ( t1.SID = t2.SID AND t1.SNAME = t2.SNAME )

Answer 2

为什么你需要同时运行36000条记录。还有什么是可行的分期付款。对于没有几个学生，只有一个分期付款。所以我认为数据库是错误的。表中每个学生应该只有一个分期金额和时间间隔（截止日期）。

检查最新的更改。这只适用于一名学生。

   Declare @student table(SID int,SNAME varchar(50),INST Date ,Amount int)
insert into @student
select 123,'XYZ','01-01-2013',3500 union all
select 123,  'XYZ',  '01-05-2013',  3500 union all
select 123,  'XYZ',  '01-10-2013',  3500 union all
select 123,  'XYZ',  '01-04-2014',  3500 union all
select 123,  'XYZ',  '01-06-2014',  3500

Declare @instalmentamount float
select @instalmentamount=amount from @student where sid=123
--select @instalmentamount
Declare @Table2 table(SID int,Paydate date,amoount int)
insert into @Table2
select 123,    '01-01-2013',  1167 union all
select 123,    '01-02-2013',  1167 union all
select 123,    '01-03-2013',  1167 union all
select 123,    '01-05-2013',  1750 union all
select 123,    '01-05-2013',  1750 union all
select 123,    '01-10-2013',  1167 union all
select 123,  '01-10-2013',  1167

declare @input date='01-01-2014'

;With CTE as
(select s.SID, sum(s.amount) as [Total Inst.Amt ] from @student s 
where s.INST<=@input
group by s.SID),
cte1 as
(
select t.SID, sum(t.amoount) as [Paid.amount] from @Table2 t 
where t.Paydate<=@input
group by t.SID
)

select c.sid,
(select top 1 s.SNAME from @student s where s.SID=c.SID) [Name],
c.[Total Inst.Amt ],c1.[Paid.amount], 
c.[Total Inst.Amt ]-c1.[Paid.amount] [BalanceAmount],cast(((c.[Total Inst.Amt ]-c1.[Paid.amount])/@instalmentamount) as int)+1 [Balance.Installments]
from CTE c inner join cte1 c1 on c.SID=c1.SID

Answer 3

尝试这个......

SELECT  t.ID,
        T.SNAME,
        T.AMT  'Total Inst.Amt as on01.01.2014',
         ISNULL(SUM(amoount),0) AS 'PAID AMT',
        T.AMT - ISNULL(SUM(amoount),0) AS 'BALANCE AMT' ,     
        CEILING((T.AMT-  ISNULL(SUM(amoount),0) )/( T.InstAmt*1.)) 'Balance.Installments'
FROM 
    (
     SELECT ID,SNAME,SUM(AMT)AMT,MAX(AMT) AS InstAmt FROM @Table1 WHERE DT_ < '01-31-2014' GROUP BY  ID,SNAME
    ) T 
     LEFT JOIN @Table2 P ON P.ID = T.id AND P.Paydate < '01-31-2014'
 GROUP BY t.ID,SNAME,t.InstAmt,T.AMT

平衡分期付款的数量

3 个答案: