我有一个名为$insert_users
的数组如下:
Array
(
[0] => 9def02e6337b888d6dbe5617a172c18d
[1] => a6d22e4cc3f65778a60b359842bcec82
[2] => e17151c98358b60910d4d9fd6ae73ac4
[3] => 472d3d7eca74cb3518bcba787aee8540
)
现在我必须从上面的数组中为每个id发出一个SQL查询。我为此编写的代码如下:
foreach($insert_users as $key => $value ) {
$sql = " SELECT DISTINCT ud.user_mobile_number, u.user_first_name, u.user_last_name FROM OCN.users_groups_subscribe ugs JOIN OCN.users_details ud ON ud.user_id=ugs.subscribe_user_id JOIN OCN.users u ON u.user_id=ugs.subscribe_user_id WHERE ugs.subscribe_user_id ='".$value."'";
$this->mDb->Query( $sql);
$students_data = $this->mDb->FetchArray();
}
它返回来自$insert_users
数组的单个id元素的数组:
Array
(
[0] => Array
(
[user_mobile_number] => 9929933345
[user_first_name] => Ashish
[user_last_name] => Patil
)
)
但我没有得到所需格式的数组。我想要以下格式的数组$students_data
以及数组$insert_users
中的所有值:
Array(
[0]=>Array
(
[user_full_name] => Ashish Patil //This key should be newly generated & should contain values of keys user_first_name & user_last_name concatenated to each other
[user_mobile_number] => 9929933345
)
)
此外,任何人都可以告诉我有没有办法只触发一次SQL查询并获得所需的数组,其中包含数组$insert_users
中所有ID的详细信息?
答案 0 :(得分:1)
赢得了这个帮助:
SELECT DISTINCT ud.user_mobile_number,
CONCAT(u.user_first_name,' ',u.user_last_name) AS user_full_name
FROM OCN.users_groups_subscribe ugs
JOIN OCN.users_details ud ON ud.user_id=ugs.subscribe_user_id
JOIN OCN.users u ON u.user_id=ugs.subscribe_user_id
WHERE ugs.subscribe_user_id ='".$value."'";
答案 1 :(得分:1)
而不是做
foreach($insert_users as $key => $value ) {
$sql = " SELECT DISTINCT ud.user_mobile_number, u.user_first_name, u.user_last_name FROM OCN.users_groups_subscribe ugs JOIN OCN.users_details ud ON ud.user_id=ugs.subscribe_user_id JOIN OCN.users u ON u.user_id=ugs.subscribe_user_id WHERE ugs.subscribe_user_id ='".$value."'";
$this->mDb->Query( $sql);
$students_data = $this->mDb->FetchArray();
}
待办事项
$value = "'" . implode("','", $insert_users) . "'";
$sql = " SELECT DISTINCT ud.user_mobile_number, CONCAT(u.user_first_name,' ',u.user_last_name) AS user_full_name FROM OCN.users_groups_subscribe ugs JOIN OCN.users_details ud ON ud.user_id=ugs.subscribe_user_id JOIN OCN.users u ON u.user_id=ugs.subscribe_user_id WHERE ugs.subscribe_user_id IN(" .$value . ")";
$this->mDb->Query( $sql);
$students_data = $this->mDb->FetchArray();
现在你应该在一个查询中得到你想要的所有结果