# Data Sets, Variable_Selection: Table of Columns to Select from Variable_Table
VARIABLE_SELECTION <- data.frame(Set.1 = c(3,1,1,1,1), Set.2 = c(0,3,2,2,2), Set.3 = c(0,0,3,4,3),
Set.4 = c(0,0,0,5,4), Set.5 = c(0,0,0,0,5))
VARIABLE_TABLE <- data.frame(Var.1 = runif(100,0,10), Var.2 = runif(100,-100,100), Var.3 = runif(100,0,1),
Var.4 = runif(100,-1000,1000), Var.5 = runif(100,-1,1), Var.6 = runif(100,-10,10))
# Sting rows into character string of columns to select
VARIABLE_STRING <- apply(VARIABLE_SELECTION,1,paste,sep = ",",collapse = " ")
VARIABLE_STRING <- gsub(" ",",",VARIABLE_STRING)
VARIABLE_STRING <- data.frame(VAR_STRING = gsub(",0","",VARIABLE_STRING))
# Will actually be part of lapply function but, one line selection for demonstration:
VARIABLE_SINGLE_SET <- as.character(VARIABLE_STRING[4,])
# Subset table for selected columns
VARIABLE_TABLE_SUB_SELECT <- VARIABLE_TABLE[,c(VARIABLE_SINGLE_SET)]
# Error Returned:
# Error in `[.data.frame`(VARIABLE_TABLE, , c(VARIABLE_SINGLE_SET)) :
# undefined columns selected
我知道文本格式是问题,但我找不到解决方法,有什么建议吗?
答案 0 :(得分:1)
您应该避免按列数进行子设置并按变量名称处理,或者至少将索引保留为整数列表(不需要强制转换为字符串)
首先要保持相同的想法,这会更正您的代码。 Basciaclly我强迫你的变量向量:
VARIABLE_TABLE[,as.numeric(unlist(strsplit(
VARIABLE_SINGLE_SET,',')))]
答案 1 :(得分:1)
这是否会产生预期效果?
lapply(VARIABLE_SELECTION, function(x) VARIABLE_TABLE[ , x[x != 0], drop = FALSE])
生成一个列表,其中每个元素都是'VARIABLE_SELECTION'给出的'VARIABLE_TABLE'的子集(使用'VARIABLE_TABLE',行数较少)。
# $Set.1
# Var.3 Var.1 Var.1.1 Var.1.2 Var.1.3
# 1 0.09536403 5.593292 5.593292 5.593292 5.593292
# 2 0.09086404 6.339074 6.339074 6.339074 6.339074
#
# $Set.2
# Var.3 Var.2 Var.2.1 Var.2.2
# 1 0.09536403 65.81870 65.81870 65.81870
# 2 0.09086404 66.79157 66.79157 66.79157
#
# $Set.3
# Var.3 Var.4 Var.3.1
# 1 0.09536403 -674.6672 0.09536403
# 2 0.09086404 -576.7986 0.09086404
#
# $Set.4
# Var.5 Var.4
# 1 0.5155411 -674.6672
# 2 -0.9593219 -576.7986
#
# $Set.5
# Var.5
# 1 0.5155411
# 2 -0.9593219