Question

我有以下代码：

<span class="bookings">
    <span class="col-md-2">
      <h4><%= time_tag(Date.today + 1.days) %></h4>
      <% @booking.each do |b| %>
        <% if b.date == Date.today + 1.days && b.type == "Hot Desk"  %>
          <% if b.desk == @hotdesk.code %>
            <span class="glyphicon glyphicon-remove booked-show"></span>
          <% end %>
        <% end %>
      <% end %>
    </span>
  </span>

  <span class="bookings">
    <span class="col-md-2">
      <h4><%= time_tag(Date.today + 2.days) %></h4>
      <% @booking.each do |b| %>
        <% if b.date == Date.today + 2.days && b.type == "Hot Desk"  %>
          <% if b.desk == @hotdesk.code %>
            <span class="glyphicon glyphicon-remove booked-show"></span>
          <% end %>
        <% end %>
      <% end %>
    </span>
  </span>

这延续了很多天，我想显示预订的可用性。我想要实现的只是将这些代码块中的一个编写出来并让它循环显示 Date.today + 1.days ，并将每个循环的日期值增加1到20次左右。

有关此方法的任何想法可以让我一次又一次地编写此代码吗？

Answer 1

<span class="bookings">
    <% 1.upto(YOUR_COUNT.to_i).each do |day_count| %>
    <span class="col-md-2">
      <h4><%= time_tag(Date.today + day_count.days) %></h4>
      <% @booking.each do |b| %>
        <% if b.date == Date.today + day_count.days && b.type == "Hot Desk"  %>
          <% if b.desk == @hotdesk.code %>
            <span class="glyphicon glyphicon-remove booked-show"></span>
          <% end %>
        <% end %>
      <% end %>
    </span>
    <% end %>
  </span>

循环遍历日期整数

1 个答案: