Question

我的本地主机上运行的PHP代码非常好，但是一旦我将页面上传到服务器就会有所不同，任何人都可以建议问题是什么

我不应该在其中添加这些代码的字段：<?=$firstname?>

这是我正在谈论的页面的链接：

[http://studentnet.kingston.ac.uk/k1003140/user1.php]

以下是代码：

<?php
session_start();

if(isset($_SESSION["username"])){
    header("location: user1.php"+$u);
} else {
    header ("location: index.php");
}
// see if the form has been completed
include_once("php_includes/check_login_status.php");
include_once("php_includes/db_conx.php");
// Initialize any variables that the page might echo
$u = "";
$firstname = "";
$surname = "";
$gender = "Male";
$country = "";
$weight = "";
$height = "";

if(isset($_GET["u"])){
    $u = preg_replace('#[^a-z0-9]#i', '', $_GET['u']);
} 

$sql = "SELECT * FROM users WHERE username='$u' AND activated='1' LIMIT 1";
$user_query = mysqli_query($db_conx, $sql);

// check if the user exists in the database
while ($row = mysqli_fetch_array($user_query, MYSQLI_ASSOC)) {
    $firstname = $row["firstname"];
    $surname = $row["surname"];
    $weight = $row["weight"];
    $height = $row["height"];
    $email = $row["email"];
    $gender = $row ["gender"];
}
if (isset($_POST['submit'])){
    $firstname = $_POST['firstname'];
    $surname = $_POST['surname'];
    $weight = $_POST['weight'];
    $height = $_POST['height'];
    $email = $_POST['email'];
    $gender = $_POST['gender'];
    mysql_connect ("studentnet","k1003140","k1003140"); mysql_select_db('db_k1003140');     
    // check if that user exist 
    $exists = mysql_query ("SELECT * FROM users WHERE firstname='" . $firstname . "'") or die ("query cant connect");   
    if (mysql_num_rows ($exists) != 0) {
    // update the description in the database       
        mysql_query("UPDATE users SET firstname='$firstname', surname='$surname', weight='$weight', height='$height' WHERE firstname='$firstname'") or die ("update could not be applied");
            echo "successful";
    } else echo "the name does not exist";  
}
?>

这是我的代码的PHP

    <!DOCTYPE html>
    <html>
    <head>
        <title>update MySql form</title>
    </head>
        <body>
        <div id="pageMiddle">  

            <form action="user1.php" method="POST">
                <div>
                <p>First Name: <input type="text" name="firstname" id="firstname" value="<?=$firstname?>"></p>
                <p>Surname: <input type="text" name="surname" id="surname" value="<?=$surname?>"></p>   
                <p>Weight: <input type="text" name="weight" id="weight" value="<?=$weight?>"></p>
                <p>Height: <input type="text" name="height" id="height" value="<?=$height?>"></p>
                <p> <input type="submit" name="submit" id="submit" value="Update Description"></p>
                </div>
            </form>
        </body>
    </html>

任何人都可以建议我如何让用户使用$ u而不是名字来编辑他们的详细信息，因为如果任何人有相同的名称将更改其他用户的详细信息，这也是安全的或任何人都可以更新任何人的详细信息。

Answer 1

之前PHP 5.4用于打印的短语法运算符

<?= $var ?>

要求在php.ini中启用short_open_tag

问题很可能是因为你启用了short_open_tag（或者你的测试服务器上的php版本比现有版本更新。

如果编辑php.ini并确保将其设置为

short_open_tag = On

然后重新启动您的网络服务器，这应该可以解决您的问题

如果您无法编辑php.ini，那么也可以设置short_open_tag via the .htaccess file

Answer 2

您需要检查以确保服务器上运行的PHP版本与本地开发计算机以及编译到本地PHP中的任何模块相比，因为这是开发中工作的最常见原因。不在生产中。

确认PHP版本后，可以尝试启用错误以查看错误。

Answer 3

我已将变量<? =$firstname?>更改为替代echo $firstname

当服务器停止工作时，PHP更新配置文件在本地主机上正常工作

3 个答案: