如何为以下命令行形成PHP curl请求？

Question

有人可以帮我在PHP中形成命令行请求吗？

$ curl -u [USER:PASSWORD] https://subs.pinpayments.com/api/v4/meresheep/subscribers/7388.xml

我尝试过以下操作，只返回“假”...

 // Query the user to pin payments for the details...
 $curl_url = "https://subs.pinpayments.com/api/v4/xyz-site/subscribers/32.xml";

 //open connection
 $ch = curl_init();

 //set the url, number of POST vars, POST data
 curl_setopt($ch, CURLOPT_URL, $url);
 curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
 curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
 curl_setopt($ch, CURLOPT_HTTPHEADER, array('Authorization: -u [USER:PASSWORD]'));

 //execute post
 $result = curl_exec($ch);
 curl_close($ch);

Answer 1

您需要更改CURLOPT_HTTPHEADER行：

curl_setopt($data, CURLOPT_HTTPHEADER, array(
    'Authorization: Basic ' . base64_encode('username:password')
));