Question

下面是我的字符串

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我正在尝试删除此网址

/Seitokai-Yakuindomo-2-episode-7-english-subbed-video-mirror-725130-FLVUpload/

目前我正在使用以下

$url = inbtwn($newData,'rel="nofollow" href="','-FLVUpload/">');


function inbtwn($input, $startcut, $finishcut){
    $a1 = split($startcut, $input);
    $a2 = split($finishcut, $a1[1]);
    $output = $a2[0];
return $output;
}

但是它返回了我与watsite的结果，我如何从上面的字符串块中获得/ Seitokai-Yakuindomo-2-episode-7-english-subbed-video-mirror-725130-FLVUpload /。

感谢您的帮助

Answer 1

parse_url()对您有用。

$url ='http://google.com/wrwetfrtgertger/';
$tmp = parse_url($url);
echo $tmp['path'];

或者代码不起作用。

$url ='http://google.com/wrwetfrtgertger/';
$tmp = parse_url($url);
echo $url = str_replace('http://'.$tmp['host'] ,'',$url);

Answer 2

尝试使用正则表达式快速而肮脏

$regex = '/href\\s*=\\s*"([^"]*-FLVUpload\/)/s';
if  (preg_match_all($regex, $newData, $matches_out)) {
  $url = $matches_out[1][0];
  print($url);
} else {
  print('URL not found');
}

关于PHP剪切字符串模式

2 个答案: