Question

我的XML格式如下，需要生成映射表。

<params>
     <parm suffix="1">A</parm>
     <parm suffix="2">B</parm>
     <parm suffix="3">C</parm>
     <parm suffix="4">D</parm>
     <parm suffix="5">E</parm>
 <params>

欲望输出是：parm值（A，B，C ......）映射到组合parm＆amp;后缀（A_1，B_2，C_3 ......）

A -> A_1
B -> B_2
C -> C_3
D -> D_4
E -> E_5

任何类型的格式都可以，只要我能像parmList [“A”]一样检索A_1。谢谢。

Answer 1

类似的东西：

library(XML)
xmltest <- "<params>
     <parm suffix=\"1\">A</parm>
     <parm suffix=\"2\">B</parm>
     <parm suffix=\"3\">C</parm>
     <parm suffix=\"4\">D</parm>
     <parm suffix=\"5\">E</parm>
</params>"

xmlout <- xmlInternalTreeParse(xmltest)
outattrs <- xpathApply(xmlout,"//params/parm",xmlGetAttr,"suffix")
outval <- xpathApply(xmlout,"//params/parm",xmlValue)
parmList <- setNames(Map(paste, outval, outattrs, sep="_"),outval)

#$A
#[1] "A_1"
#$B
#[1] "B_2"
#$C
#[1] "C_3"
#$D
#[1] "D_4"
#$E
#[1] "E_5"

parmList[["A"]]
#[1] "A_1"

R：将XML解析为所需的映射表

1 个答案: