我创建了一个类似的基类:
#include <cstdint>
#include <iterator>
#include <cstdint>
#include <vector>
#include <initializer_list>
class PSBaseObject
{
protected:
inline std::int32_t* size_ptr(void* Data) { return reinterpret_cast<std::int32_t*>(Data) - 1; }
inline const std::int32_t* size_ptr(void* Data) const { return reinterpret_cast<std::int32_t*>(Data) - 1; }
public:
PSBaseObject() {}
virtual ~PSBaseObject() {}
};
template<typename T>
class PSObject : public PSBaseObject
{
protected:
T Data;
inline std::int32_t* size_ptr() { return reinterpret_cast<std::int32_t*>(&Data[0]) - 1; }
inline const std::int32_t* size_ptr() const { return reinterpret_cast<std::int32_t*>(&Data[0]) - 1; }
public:
PSObject() { *size_ptr(&Data[0]) = 0; *(size_ptr(&Data[0]) - 1) = -1; }
virtual ~PSObject() {}
};
然后我继承PSObject
(不是PSBaseObject
),就像这样:
template<typename T>
class PSArray : public PSObject<std::vector<T, CustomAllocator<T>>>
{
private:
typedef std::vector<T, CustomAllocator<T>> underlying_type;
public:
typedef std::size_t size_type;
typedef std::ptrdiff_t difference_type;
typedef T* pointer;
typedef const T* const_pointer;
typedef T& reference;
typedef const T& const_reference;
typedef T value_type;
typedef typename underlying_type::iterator iterator;
typedef typename underlying_type::iterator::const_iterator const_iterator;
typedef std::reverse_iterator<const_iterator> const_reverse_iterator;
typedef std::reverse_iterator<iterator> reverse_iterator;
explicit PSArray() : Data(CustomAllocator<T>()) { *size_ptr() = 0; }
explicit PSArray(size_type size) : Data(size, CustomAllocator<T>()) { *size_ptr() = size - 1; }
explicit PSArray(size_type size, const T &value) : Data(size, std::forward<decltype(value)>(value), CustomAllocator<T>()) { *size_ptr() = size - 1; }
};
int main()
{
}
它告诉我:
error: class ‘PSArray<T>’ does not have any field named ‘Data’
为什么它没有从基类中看到“数据”字段?还有一种方法可以将我的typedef移动到基类并让子类仍能看到它们吗?
答案 0 :(得分:1)
您无法在派生类中初始化基类的Data
字段;您需要提供一个构造函数来获取类型为T
的对象,然后基类构造函数可以使用该值初始化Data
。