Question

我在我的页面中有ajax函数从其发布的php加载数据。唯一的问题是数据不会从php页面返回。请查看并告诉我代码中是否有任何错误。任何帮助非常感谢。这一切都应该没有让人耳目一新。

$('#filterByPrice button', '#filterByPrice button').click(function(e){
    e.preventDefault();
    var form = $(this).closest('form');
    $.ajax({
        url: 'filter-data.php' ,
        type: 'POST',
        data: form.serialize(),
        success: function(data){
            $('.container').html("");
            $('.container').html(data);
        }
    });


});

PHP文件是：

<?php 

if(isset($_POST['filter'])){

    $searchStr = $_SESSION['searchString'];
    $filter = $_POST['filter'];
    if(!is_array($filter)){
        require_once('Connections/conn.php');

        $stmt = $conn->prepare( "SELECT * FROM happyhours
        WHERE (city LIKE :keyword OR zipcode LIKE :keyword)
        AND cost = '$filter'");
    }
    else {
        $filter = implode(', ', $_POST['filter']);
        require_once('Connections/conn.php');

        $stmt = $conn->prepare( "SELECT * FROM happyhours
        WHERE (city LIKE :keyword OR zipcode LIKE :keyword)
        AND dayOfTheWeek LIKE '$filter'");
    }

            try{
                $stmt->execute(array(':keyword' => $searchStr.'%'));
                }
            catch(PDOException $ex){
                echo $ex->getMessage();
                }
        $count = $stmt->rowCount();
        $each = $stmt->fetch(PDO::FETCH_ASSOC);

        if ($count > 0){

        do {

        echo '<table id="results" width="700px" border="0">
      <tr>
        <td rowspan="5" width="130" id="photo"><a class="lightbox" href="'.$each['imageURL'].'"><p>'.$each['name'].'</p><img id="hh-image" src="'.$each['imageURL'].'" width="80" height="80" /></a></td>

        <tr><td id="hh-name" style="word-wrap:break-word; font-size:16px; font-family:\'Myriad Pro\'; font-weight:500" width="560" height="20"><'.$each['name'].'</td></tr>

         <tr><td> <a href="'.$each['googleMap'].'" target="new" style="font-size:14px">'.$each['address'].'</a></td>
      </tr>
      <tr>
        <td style="word-wrap:break-word; font-size:14px; font-family:\'Myriad Pro\'" height="20">'.$each['phone'].'</td>
      </tr>
      <tr>
        <td style="word-wrap:break-word; font-size:14px; font-family:\'Myriad Pro\'" height="20">'.$each['dayOfTheWeek'].'&nbsp;&nbsp;('.$each['hours'].')</td>
      </tr>
    </table>';
} while($each = $stmt->fetch(PDO::FETCH_ASSOC));

}

}

 ?>

Answer 1

您不能在查询中多次重复使用相同的:keyword占位符，您必须为它们指定不同的名称。

if(!is_array($filter)){
    require_once('Connections/conn.php');

    $stmt = $conn->prepare( "SELECT * FROM happyhours
    WHERE (city LIKE :city OR zipcode LIKE :zip)
    AND cost = :filter");
}
else {
    $filter = implode(', ', $_POST['filter']);
    require_once('Connections/conn.php');

    $stmt = $conn->prepare( "SELECT * FROM happyhours
    WHERE (city LIKE :city OR zipcode LIKE :zip)
    AND dayOfTheWeek LIKE :filter");
}

try{
    $stmt->execute(array(':city' => $searchStr.'%',
                         ':zip' => $searchStr.'%',
                         ':filter' => $filter));
}
catch(PDOException $ex){
    echo $ex->getMessage();
}

php没有返回数据来查询ajax函数

1 个答案: