我试图让Hashset中的一个响应在我输入hi时显示但是它显示了hashset中的所有项目,任何任何帮助都会在下面感谢我的代码。
public class tst {
public static void main(String[] args){
Scanner input=new Scanner(System.in);
HashMap<String,HashSet> map = new HashMap<String, HashSet>();
HashSet<String>hs=new HashSet<String>();
Random r = new Random();
hs.add("How are you");
hs.add("Whats up");
hs.add("How Have You Been");
hs.add("Missed Me");
hs.add("ab");
hs.add("cd");
hs.add("Excuse me no no");
map.put("hi",hs);
System.out.println("enter Hi");
String str=input.next().toLowerCase().trim();
if(map.containsKey(str)){
System.out.println(map.get(str));
}
}
}
答案 0 :(得分:0)
我更改了您的代码并使用了ArrayList<String>
而不是HashSet<String>
。我不知道在你的进一步设计中你是否需要它是HashSet
但是ArrayList
你可以通过它们的索引检索元素 - 并且索引很容易随机获得:
public static void main(String args[]) {
Scanner input = new Scanner(System.in);
// the HashMap now needs to store Strings and ArrayLists
HashMap<String, ArrayList<String>> map = new HashMap<String, ArrayList<String>>();
// the ArrayList replaces your HashSet.
ArrayList<String> list = new ArrayList<String>(); // I called it list so you we can see the difference :)
Random r = new Random();
list.add("How are you");
list.add("Whats up");
list.add("How Have You Been");
list.add("Missed Me");
list.add("ab");
list.add("cd");
list.add("Excuse me no no");
map.put("hi", list);
System.out.println("enter Hi");
String str = input.next().toLowerCase().trim();
if (map.containsKey(str)) {
ArrayList<String> tmpList = map.get(str); // this is just make the step clear, that we now retrieve an ArrayList from the map
int randomNumber = r.nextInt(tmpList.size()) // a random number between 0 and tmpList.size()
System.out.println(tmpList.get(randomNumber)); // get the random response from the list
}
}
当我测试它时结果如下:
enter Hi
Hi
How Have You Been