Question

我想从服务器向客户端发送200 x 200个数组（每个“行”4个）。但我必须将其添加到服务器，以便客户端接收所有数据

while(true){
    Bw.write("end");
    Bw.write("\n");
}

没有它，客户端只接收第一个194 x 200和1 x 32，然后不接收mo数据。

我必须做些什么而不等待while（true）中的异常？

服务器：

ServerSocket ssocket = new ServerSocket(PORT_NUMBER);
Socket socket = ssocket.accept();
BufferedWriter Bw = new BufferedWriter(new OutputStreamWriter(socket.getOutputStream()));

socket.setTcpNoDelay(true);
//load from XML 
SAXBuilder builder = new SAXBuilder();
File xmlFile = new File("res/map.xml");
Document doc = (Document) builder.build(xmlFile);
Element root = doc.getRootElement();

int sz = root.getAttribute("sizeZ").getIntValue();
int sx = root.getAttribute("sizeX").getIntValue();
data = new float[sz][sx];
data2 = new int[sz][sx];
Bw.write(String.valueOf(sz));
Bw.write(" ");
Bw.write(String.valueOf(sx));
Bw.write("\n");
for(Object o : root.getChildren()){
    Element e = (Element) o;
    int z = e.getAttribute("z").getIntValue();
    int x = e.getAttribute("x").getIntValue();
    int y = e.getAttribute("y").getIntValue();
    int g = (int)e.getAttribute("g").getFloatValue();
    data[z][x] = y;
    data2[z][x] = g;
    Bw.write(String.valueOf(z));
    Bw.write(" ");
    Bw.write(String.valueOf(x));
    Bw.write(" ");
    Bw.write(String.valueOf(y));
    Bw.write(" ");
    Bw.write(String.valueOf(g));
    Bw.write("\n");
}
Bw.write("end");
Bw.write("\n");
while(true){
    Bw.write("end");
    Bw.write("\n");
}

客户端：

socket = new Socket("127.0.0.1", 1080);
System.out.println("úspěšné připojení");
socket.setTcpNoDelay(true);
BufferedReader Br = new BufferedReader(new InputStreamReader(socket.getInputStream()));

String[] s;
String st;
st = Br.readLine();
System.out.println(st);
s = st.split(" ");
data = new float[Integer.parseInt(s[0])][Integer.parseInt(s[1])];
data2 = new int[Integer.parseInt(s[0])][Integer.parseInt(s[1])];
st = Br.readLine();
s = st.split(" ");
while(!s[0].equals("end")){
    int z = Integer.parseInt(s[0]);
    int x = Integer.parseInt(s[1]);
    int y = Integer.parseInt(s[2]);
    int g = Integer.parseInt(s[3]);
    data[z][x] = y;
    data2[z][x] = g;
    st = Br.readLine();
    s = st.split(" ");
}

Answer 1

您只需在完成（真实）数据写入后调用bw.flush()。

虽然我引起了你的注意，但这些风格很糟糕：

  BufferedReader Br =                     // should be br
  BufferedWriter Bw =                     // should be bw

并且您的客户端和服务器端代码看起来都可能泄漏文件描述符。

java socket无法工作和分离工作所需的冗余代码

1 个答案: