首先,让我告诉你我到目前为止的代码:
public void populateArray(){
//NOTE: THIS METHOD SHOULD BE RUN FIRST. Many of the methods in this class rely on a populated file array to function.
// This method will populate our file array.
// First, we note the directory we want to pull files from.
File folder = new File("HR");
File dir = new File("");
File file = new File("");
//Then we fill an array with the list of documents in that directory
//This will also include folders.
int count = 0;
allDocs = folder.listFiles();
int fileCount = 0;
int dirCount = 0;
System.out.println("Displaying contents of directory...");
while (count < allDocs.length){
System.out.println("Found: " + allDocs[count]);
count++;
}
System.out.println("Sorting directories and files separately...");
count = 0;
while (count < allDocs.length){
if (allDocs[count].isDirectory()){
dir = new File(allDocs[count].getPath());
dirs[dirCount] = dir;
System.out.println("Document " + allDocs[count].getPath() + " sorted into -Directory- array at position " + dirCount);
dirCount++;
}
else{
file = new File(allDocs[count].getPath());
files[fileCount] = file;
System.out.println("Document " + allDocs[count].getPath() + " sorted into -File- array at position " + fileCount);
fileCount++;
}
count++;
}
return;
}
files,dirs和allDocs是在任何方法之外的类中声明的数组。
allDocs是我用来获取感兴趣的目录HR中的每个目录和文件的数组。我使用allDocs = folder.listFiles();
执行此操作我希望文件成为存储HR目录中所有文件的数组,我希望dirs是存储HR中所有目录的数组,但我不想存储任何内容人力资源部门的董事。
我尝试使用println“单独排序目录和文件”下的循环执行此操作。
问题在于:
else{
file = new File(allDocs[count].getPath());
files[fileCount] = file;
System.out.println("Document " + allDocs[count].getPath() + " sorted into -File- array at position " + fileCount);
fileCount++;
}
这是因为allDocs中的第一个元素是一个文件。当第一个元素是目录时,也会出现此问题。问题是文件[fileCount] =文件上的空指针异常;线,我不明白。 “file”不为null,我只是给它赋了一个值。当然,在这种情况下,文件[fileCount]为null,但是如果我为它分配值,为什么会这样呢?
文件声明:
public class Methods
{
private static File[] files;
答案 0 :(得分:4)
您可能更愿意简化:
List<File> fileList = new ArrayList<>();
List<File> dirList = new ArrayList<>();
while (count < allDocs.length){
if (allDocs[count].isDirectory()){
dirList.add(allDocs[count]);
System.out.println("Document " + allDocs[count].getPath()
+ " sorted into -Directory- array at position " + dirCount);
dirCount++;
}
else{
fileList.add[allDocs[count]);
System.out.println("Document " + allDocs[count].getPath()
+ " sorted into -File- array at position " + fileCount);
fileCount++;
}
count++;
}
dirs = dirist.toArray(new File[dirList.size()]);
dirCount = dirs.length;
files = fileList.toArray(new File[fileList.size()]);
fileCount = files.length;
使用List<File>
代替File[]
似乎是合适的,因为您事先并不知道数组大小,并且您需要:
File[] files = new File[n];
如果打算填写文件:
files[fileCount] = ...
答案 1 :(得分:3)
您可能忘记分配数组 - 如下所示:
java.io.File [] files = new java.io.File[10];
如果您只是这样声明:
java.io.File [] files;
files
将为null
而files[fileCount]
将导致NullPointerException
。
如评论中所述,您可能希望将其更改为:
java.util.List<java.io.File> files = new ArrayList<>();
并添加如下文件:
files.add(file);
这样您就不必提前知道参赛作品的数量。