Question

我正在尝试删除与传入方法的字符串匹配的行。

$conn = new PDO("mysql:host=$dbhost;dbname=$dbname",$dbuser,$dbpass);
$data = array($_POST["username"]);


$stmt = $conn->prepare("DELETE FROM Table WHERE username = username=? ");
$stmt->execute($data);

我尝试了一些SQL语句的组合，但无法让它工作

Answer 1

// Store user input in a variable
$data =  $_POST["username"];

// Prepare the query
$stmt = $conn->prepare("DELETE FROM Table WHERE username=:username");

// Bind the value
$stmt->bindValue(':username', $data, PDO::PARAM_STR);

// Execute the query
$success = $stmt->execute();

// If query succeeded, display the number of affected rows
if ($success) {
    $affected_rows = $stmt->rowCount();
    echo $affected_rows;
}

Answer 2

发现SQL错误：

username = username=?

应该是

username = ?

PHP用字符串删除一行

2 个答案: