我正在尝试构建一个霍夫曼编码树。
主要
int main()
{
// Read frequency table and build Huffman tree.
NodePtr huffman = build_tree();
print_tree(huffman);
// Free the allocated memory.
free_memory(huffman);
return 0;
}
输入应该在表格中:
number of letters
"letter" number of occurrences
"letter2" number of occurrences
到目前为止,我还没有工作。什么想法可能是错的?
build_tree函数:
NodePtr build_tree()
{
int characters;//number of characters
cin >> characters;
char letter;
int freq;
HuffmanPriorityQueue queue;
NodePtr p;
for (int i = 0 ; i < characters; i++)
{
cin >> letter;
cin >> freq;
NodePtr temp = new HuffmanNode(freq, letter);
queue.push(temp);
}
for (int i = 0 ; i < characters - 1 ; i++)
{
NodePtr a = queue.top();
queue.pop();
NodePtr b = queue.top();
NodePtr p = new HuffmanNode (a->frequency + b->frequency, NULL);
queue.push(p);
}
return p;
}
打印功能:提供了哪个,所以我认为它是正确的。
void print_tree(NodePtr root, int indent = 0, string prefix = "")
{
// External nodes are not printed.
if (root == NULL) {
return;
}
char letter = ' ';
if (root->is_leaf()) {
letter = root->letter;
}
cout << string(indent, ' ') << prefix << "(" << letter << " [" << root->frequency << "]";
if (root->is_leaf()) {
cout << ")" << endl;
} else {
cout << endl;
// Print left and right subtrees with the appropriate prefix, and
// increased indent (by INDENT_SIZE).
print_tree(root->left, indent + INDENT_SIZE, "0");
print_tree(root->right, indent + INDENT_SIZE, "1");
cout << string(indent, ' ') << ")" << endl;
}
}
答案 0 :(得分:3)
你有几个问题:
NodePtr p
。pop
NodePtr b
a
和b
以下可能有所帮助:
for (int i = 0 ; i < characters - 1 ; i++)
{
NodePtr a = queue.top();
queue.pop();
NodePtr b = queue.top();
queue.pop();
NodePtr p = new HuffmanNode (a, b); // The new node has two children `a` and `b`.
queue.push(p);
}
return queue.top(); // Return root.